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butalik [34]
3 years ago
12

Which of the following must be true for and expression to be a difference of two squares?

Mathematics
2 answers:
Rudik [331]3 years ago
5 0
<span>Let's say e=a^2−b^2 and take each affirmation:

a. </span><span>both coefficients are perfect squares.
</span><span>a could be equal to 2 which is not a perfect square 

b. </span><span>there are only two terms - obviously yes
</span><span>
c. </span>both terms have negative coefficients - as we can see just b has a negative <span>coefficient

Final answer b. </span><span>there are only two terms.</span>
<span>

</span>
Soloha48 [4]3 years ago
3 0

The <em><u>correct answers</u></em> are:

a. both coefficients are perfect squares.; and b. there are only two terms.

Explanation:

In order to have a difference of squares, we will have only two terms.  Algebraically, this can be represented by a²-b².  This is by definition.

Since this is the difference of <em>squares</em>, both terms must be perfect squares.  If they are not, then it is no longer the difference of squares.

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Matrix multiplication was used to encode a message using the given encoding matrix: [i 47 A=1 |-1 -3] The original message was c
nadya68 [22]

Answer:

A^{-1}=\left[\begin{array}{cc}-3&-4\\1&1\end{array}\right] message SHOW_ME_THE_MONEY_  

Step-by-step explanation:

The matrix

A=\left[\begin{array}{cc}1&4\\-1&-3\end{array}\right]\rightarrow |A|=(1 \times -3)-(-1\times 4)=1\\\rightarrow A^{-1}=\left[\begin{array}{cc}-3&-4\\1&1\end{array}\right] \\

We can check that in fact A*A^⁻1=I_2 the identity matrix of size 2 x 2.

Now the message was divided in 1 x 2 matrices, then we have that the sequence given is the result of multiplying m by A, so to get m again we multiply now by A^⁻1. and we get the next table

Encoded message    Decoded message    message in letters by association

11 52        19 8    S H

-8 -9         15 23  O W

-13 -39        0 13   _ M

5 20         5 0   E _

12 56        20 8    T H

5 20         5 0    E _

-2 7           13 15  M O

9 41         14 5   N E

25 100       25 0    Y _

Then the message decoded is SHOW_ME_THE_MONEY_                                

3 0
3 years ago
Can someone please tell me the answer on this.
marishachu [46]

Answer: x = 31

Step-By-Step:

<u>To Find x:</u>

<u />\left(2x+20\right)+\left(x+10\right)+\left(2x-5\right)=180 (Angle Sum Property Of Triangles)

(Remove the brackets)

<u />2x+20+x+10+2x-5=18<u />

(Group Accordingly)

<u />2x+x+2x+20+10-5=180<u />

= 5x+20+10-5=180

= 5x\:+\:25 =180

= 5x= 180 - 25

= 5x = 155

= x=\frac{155}{5}

= 31

<u>Therefore</u> x = 31

So,

Angle A = x + 10 = 31 + 10 = 41

Angle B = 2*x + 20 = 2*31 + 20 = 82

Angle C = 2*x - 5 = 62 - 5 = 57

5 0
2 years ago
I need help with this please ASAP!!!!!
Darina [25.2K]

Answer:

Step-by-step explanation:

cant read question plz resend in the cmments so i can  answer plz

4 0
3 years ago
The ________ could be used to describe a data set by itself, while ___________ would almost never be used to describe a data set
Alona [7]

The mean could be used to describe a data set by itself, while interquartile range would almost never be used to describe a data set by itself.

<h3>What is Descriptive statistics?</h3>

These are operations which are used to summarize certain characteristics a set of data has.

Mean and range deals with the full set of data while interquartile range measures just the middle half of the data and is denoted as option A.

Read more about Descriptive statistics here brainly.com/question/6990681

#SPJ1

8 0
1 year ago
If BD is both the altitude and median of ΔABC then ΔABC is _____.
frutty [35]
The answer is C./isoceles
7 0
3 years ago
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