From the equation we see that the center of the circle is at (-2,3) and the radius is 9.
So using the distance formula we can see if the distance from the center to the point (8,4) is 9 units from the center of the circle...
d^2=(8--2)^2+(4-3)^2 and d^2=r^2=81 so
81=10^2+1^2
81=101 which is not true...
So the point (8,4) is √101≈10.05 units away from the center, which is greater than the radius of the circle.
Thus the point lies outside or on the exterior of the circle...
Answer:
The domain is the set of x values for which the function resides in.
In this graph, it is unclear as to if the function goes on to infinity, but if it does, the answer is quite easily:
(-2, 4] and [7, ∞)
since the function starts on the left at -2 then continues to the right, with a pause, then indefinitely after.
<span>13⁄41 + 27⁄82 = 26/82 + 27/82 = 53/82
3 5/24 + 6 7/24 + 4 9/24 = 13 20/24 = 13 5/6
</span><span>5 2⁄3 + 29⁄69 + 6 21⁄23 = 5 46/69 + 29/69 + 6 63/69 = 11 138/69 = 13
</span>
<span>3 9⁄10 + 4⁄9 + 7⁄45 + 4 = 3 81/90 + 40/90 + 14/90 + 4 = 7 135/90 = 8 1/2
</span><span>6 – 7⁄15 = 5 15/15 - 7/15 = 5 6/15
</span><span>11 3⁄8 – 7⁄8 = 10 11/8 - 7/8 = 10 4/8 = 10 1/2
</span><span> 7 1⁄6 – 3 4⁄9 = 7 9/54 - 3 18/54 = 6 63/54 - 3 18/54 = 3 45/54 = 3 5/6
</span>
<span>5 3⁄8 – 3 2⁄5 = 5 15/40 - 3 16/40 = 4 55/40 - 3 16/40 = 1 39/40</span>
Answer:
The 6th term of the sequence is 25
Step-by-step explanation:
first term = a = 5
common difference = d = 4
The nth term of a sequence is
T_n = a + (n - 1)d
Therefore, the 6th term of the sequence is
T_6 = a + (6 - 1)d
T_6 = a + 5d
T_6 = 5 + 5(4)
T_6 = 5 + 20
T_6 = 25
Answer:
the star is quadrant 2
Step-by-step explanation:
