All categories

3 years ago

G is between E and H, and F is the midpoint of EG. If FG=2 and FH=8, find EH.

Mathematics

1 answer:

kykrilka [37]3 years ago

8 0

Answer:

EH = 10

Step-by-step explanation:

Because F is a midpoint, that means that FG and EF are congruent to each other. So, since FG = 2, that means that EF also equals 2. Because FH also includes FG, you can take the 2 from the FG, and then take that 2 away from 8. Now you know that GH = 6. All that is left is to add all 3 of the units together (2+2+6=10).

You might be interested in

Two trucks leave a warehouse at the same time. one travels due west at an average speed of 49 miles per hour, and the other trav

Gre4nikov [31]

Well there can be two different solutions for this but i will choose the easier one. Obviously one requires a system of equations which obviously will involve a lot of thinking and some good algebra solving in order for them to solve.

So we can just keep adding the distance as we know they are in different directions. 49 + 65 = 114. So 114 * 4.5 = 513 miles. SO after around 4.5 hours they will be 513 miles apart.

4 0

3 years ago

A heavy rope, 50 ft long, weighs 0.6 lb/ft and hangs over the edge of a building 120 ft high. Approximate the required work by a

Anastasy [175]

Answer:

Exercise (a)

The work done in pulling the rope to the top of the building is 750 lb·ft

Exercise (b)

The work done in pulling half the rope to the top of the building is 562.5 lb·ft

Step-by-step explanation:

Exercise (a)

The given parameters of the rope are;

The length of the rope = 50 ft.

The weight of the rope = 0.6 lb/ft.

The height of the building = 120 ft.

We have;

The work done in pulling a piece of the upper portion, ΔW₁ is given as follows;

ΔW₁ = 0.6Δx·x

The work done for the second half, ΔW₂, is given as follows;

ΔW₂ = 0.6Δx·x + 25×0.6 × 25 = 0.6Δx·x + 375

The total work done, W = W₁ + W₂ = 0.6Δx·x + 0.6Δx·x + 375

∴ We have;

W = $2 \times \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= 2 \times \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 750$

The work done in pulling the rope to the top of the building, W = 750 lb·ft

Exercise (b)

The work done in pulling half the rope is given by W₂ as follows;

$W_2 = \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 562.5$

The work done in pulling half the rope, W₂ = 562.5 lb·ft

6 0

2 years ago

I need to determine each angles measure. M 4<br><br> M 6

Ulleksa [173]

By geometrical inspection we have:
M4 = 30
Then the angle M6 can be determined from the fact that you have a rectangle triangle (345) that has an angle of 90 and another of 30. The missing angle measures:
180-90-30 = 60 = M3
Then to find M6 we have
M3 + 60 + M6 = 180
M6 = 180-60-M3
M6 = 180-60-60
M6 = 60
answer:
M4 = 30
M6 = 60

7 0

3 years ago

BRAINLIEST, hurry please!!

tester [92]

The answer i D because 11-6=5

8 0

2 years ago

I need to classify what triangle this is and these are the choices equilateral, isosceles, scalene and right. Someone please hel

Drupady [299]

Answer:

Isosceles

Step-by-step explanation: