Answer:
4(k - 3)(3k + 5)
Step-by-step explanation:
Given
12k² - 16k - 60 ← factor out 4 from each term
= 4(3k² - 4k - 15) ← factor the quadratic
Consider the factors of the product of the coefficient of the k² term and the constant term which sum to give the coefficient of the k term
product = 3 × - 15 = - 45 , sum = - 4
Factors are - 9 and + 5
Use these factors to split the middle term
3k² - 9k + 5k - 15 → ( factor the first/second and third/fourth terms
= 3k(k - 3) + 5(k - 3) ← factor out (k - 3)
= (k - 3)(3k + 5)
Hence
12k² - 16k - 60 = 4(k - 3)(3k + 5) ← in factored form
Answer:
5
8
3
15
8
16
6
6
10
3
3
9
14
6
9
9
Step-by-step explanation:
Answer:
x = 58 degrees
Step-by-step explanation:
Angle K (which is x) and Angle I are congruent corresponding angles with one another, so if, as an example, Angle I was 10, Angle K would also be 10.
<u><em>All you need to do in this case is add Angle H (56) and Angle A (66) together:</em></u>
56 + 66 = 122
<u><em>Then subtract 122 from 180 (because triangles add up to 180 degrees) to get x:</em></u>
180 - 122 = 58
So, x = 58 degrees.
Answer:
Volume: 
Ratio: 
Step-by-step explanation:
First of all, we need to find the volume of the hemispherical tank.
The volume of a sphere is given by:
where
r is the radius of the sphere
V is the volume
Here, we have a hemispherical tank: a hemisphere is exactly a sphere cut in a half, so its volume is half that of the sphere:
Now we want to find the ratio between the volume of the hemisphere and its surface area.
The surface area of a sphere is
For a hemisphere, the area of the curved part of the surface is therefore half of this value, so 
. Moreover, we have to add the surface of the base, which is 
. So the total surface area of the hemispherical tank is
Therefore, the ratio betwen the volume and the surface area of the hemisphere is
Answer:
1. 21x⁴+3y-35x² + 41
2. -21x⁴-3y+6x² + x
Step-by-step explanation:
When adding and subtracting polynomials , you can use the distributive property to add or subtract the coefficients of like terms.
1. The polynomial is 21x⁴ + 3y -6x² + 34
To obtain polynomial 29x² -7 , we must subtract some polynomial from it.
Let that polynomial be k.
So, 21x⁴ + 3y -6x² + 34 - k = 29x² -7
k = 21x⁴ + 3y - 6x² +34 - 29x² +7 = 21x⁴ + 3y - 35x² + 41
2. To obtain a first degree polynomial, let that polynomial be x +34
So, 21x⁴ + 3y - 6x² + 34 + K = x + 34
K = x + 34 - 21x⁴ -3y + 6x² - 34
= -21x⁴ - 3y + 6x² + x
