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alexandr402 [8]
3 years ago
11

A cube has 4 inch edges what is its volume

Mathematics
1 answer:
denis23 [38]3 years ago
4 0
64 inches. 4*4*4=64. You take all the sides and multiply them together. Hope this is what u we're looking for
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43 over 50 0.91 7 over 8 84% least to greatest
Gre4nikov [31]
Make them all decimals or all fractions with the same denominator and it will be easy to tell by inspection which is least.

43/50= .86
.91=.91
7/8= .875
84%=.84

84%. 43/50. 7/8. .91
3 0
3 years ago
PLZ help 15 points math
-Dominant- [34]
B hope this helps. ‘’’’
4 0
3 years ago
Read 2 more answers
A certain country has $10 billion in paper currency in circulation, and each day $50 million comes into the country's banks. The
mash [69]

Answer:

\bf x(t)=10(1-e^{-0.005*t})

Step-by-step explanation:

The differential equation

\bf \displaystyle\frac{dx}{dt}=0.005(10-x)

can be solved by separation of variables. Write the equation as

\bf \displaystyle\frac{dx}{10-x}=0.005dt

Integrate on both sides

\bf \int\displaystyle\frac{dx}{10-x}=\int0.005dt\Rightarrow -ln(10-x)=0.005t+C\Rightarrow\\\\\Rightarrow ln(10-x)^{-1}=0.005t+C\Rightarrow (10-x)^{-1}=e^{0.005t}e^C

where C is a constant.

\bf e^C is also a constant and we will keep calling it C, (there is no reason to change the letter). We have then

\bf (10-x)^{-1}=Ce^{0.005t}\Rightarrow \displaystyle\frac{1}{10-x}=Ce^{0.005t}\Rightarrow 10-x=\displaystyle\frac{1}{Ce^{0.005t}}\Rightarrow\\\\\Rightarrow x(t)=10-(1/C)e{-0.005t}

(1/C) is a constant, and for the same reason we will keep calling it C. So the general solution is

\bf x(t)=10-Ce^{-0.005t}

Now, we use the initial condition x(0)=0

\bf x(0)=10-Ce^{-0.005*0}=0\Rightarrow C=10

and the particular solution is

\bf x(t)=10-10e^{-0.005*t}=10(1-e^{-0.005*t})\\\\\boxed{x(t)=10(1-e^{-0.005*t})}

7 0
3 years ago
If vertices of a triangle are A (5, 0), B (x, y) and C (25, 0), what is the area of the triangle?(1) |x| = y = 10(2) x = |y| = 1
Elanso [62]

Answer:

10|y|

Step-by-step explanation:

We have been given that the vertices of a triangle are A (5, 0), B (x, y) and C (25, 0). We are asked to find the area of the given triangle.

We will use area formula for triangle with vertices A, B and C as given below:

|\frac{A_x(B_y-C_y)+B_x(C_y-A_y)+C_x(A_y-B_y)}{2}|

Upon substituting the given coordinates of points A, B and C in above formula, we will get:

|\frac{5(y-0)+x(0-0)+25(0-y)}{2}|

|\frac{5(y)+x(0)+25(-y)}{2}|

|\frac{5y+0-25y}{2}|

|\frac{-20y}{2}|

|-10y|

10|y|

Therefore, the area of the given triangle would be 10|y|.

4 0
3 years ago
-8=32-5q<br><br>how would I solve this
Alex

-8=32-5Q

5Q=32+8

5Q=40

Q=8

6 0
4 years ago
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