3 years ago

X2 is the GCF of this polynomial.

Mathematics

2 answers:

MAVERICK [17]3 years ago

7 0

Answer:

the answer is B

Step-by-step explanation:

nadezda [96]3 years ago

6 0

Answer:

Step-by-step explanation:

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Find the dimensions of a rectangle with area 3 square meters whose perimeter is as small as possible.

Sveta_85 [38]

Answer:

The perimeter is minimum for Length and width both are $\sqrt3$ .

Step-by-step explanation:

Area, A = 3 square metre

Let the length is L and width is W.

Area = L W

3 = L W.....(1)

The perimeter is given by

P = 2 (L + W)

Substitute the value of from (1)

$P = 2 \left ( L +\frac{3}{L} \right )\\\\P = 2 L + \frac{6}{L}\\\\\frac{dP}{dL} = 2 - \frac{6}{L^2}\\\\Now\\\\\frac{dP}{dL}=0\\\\2 - \frac{6}{L^2} = 0\\\\L = \sqrt 3, W = \sqrt 3$

Now

$\frac{d^2P}{dL^2}=\frac{12}{L^3}\\$

It is alays positive, so the perimeter is minimum.

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2 years ago

Solve P = Check P-2w 2 = 1 for P.

GaryK [48]

Answer:

P= 2l + 2W

Step-by-step explanation:

(P-2W)/2= l

(P-2W)= 2l

P-2W= 2l

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1 year ago