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defon
4 years ago
5

What does a decreasing slope means in terms of distance?

Mathematics
1 answer:
Tpy6a [65]4 years ago
5 0
A decreasing slopes in terms of distance means to go back to the start in a certain rate

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In 3 and 4, Classify each triangle by its sides and then by its angles
romanna [79]

Answer:

3. Sides: Equilateral

Angles: Acute

4. Sides: Isosceles

Angles: Right

Step-by-step explanation:

3. Sides: Equilateral because in an equilateral triangle all sides are equal.

Angles: Acute because in an acute triangle all angles are acute.

4. Sides: Isosceles because in an isosceles triangle two legs are equal.

Angles: Right because in a right triangle, one angle is right.

7 0
3 years ago
Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of
IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable <em>X</em> following a Binomial distribution with parameters <em>n </em>and <em>p</em>.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

  • np ≥ 10
  • n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.10=1

Thus, a Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

8 0
3 years ago
Shontel has a job as a barista at a local coffee shop that pays $12 per hour. She works between 15 and 25
SIZIF [17.4K]
A. Independent is 12.5
B. Domain
Minimum is 15 maximum is 25

C. When she works for 11 hours she will earn $137.5

Hope this helps!
5 0
4 years ago
Pleaseeeee helpp!!!!!!!
erica [24]

B-corresponding

E-included Angles

C-included side

D-Linear pair

A-Adjacent angles





5 0
3 years ago
Point Q is 5 units tight and 2 units down from what point
gogolik [260]

Answer:

take the number (x,y) take Y subtract 2.. take x add 5. if the origin is 0,0 it would end 5,-2. if Q is 7,3

7+5 = 12

-3-2 = -5

answer (12,-5)

Step-by-step explanation:

5 0
3 years ago
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