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irinina [24]
3 years ago
8

The graph of f(x) = x2 is translated to form g(x) = (x – 5)2 + 1. Which graph represents g(x)?

Mathematics
2 answers:
levacccp [35]3 years ago
6 0
<span>The graph would be translated 5 units right and 1 unit up, giving an upward facing parabola with a vertex at (5, 1).

Explanation:
Since 5 was subtracted from x before it was squared, this means a horizontal translation 5 units. Since it was subtracted, this means it was translated right 5 units.

The 1 added at the end means it was translated 1 unit up as well.

This is in vertex form, y=a(x-h)^2 + k, where (h, k) is the vertex; h corresponds with 5 and k corresponds with 1, so the vertex is at (5, 1).</span>
Fofino [41]3 years ago
6 0

Answer:

Function f(x) is translated 5 units to the right and 1 unit upwards to get g(x) shown below.

Step-by-step explanation:

We are given that,

The function f(x)=x^2 is translated to form the function g(x)=(x-5)^2+1.

So, we see that,

The function f(x) is translated 5 units to the right which gives the function (x-5)^2.

Further, this function is translated to 1 unit upwards which gives the function g(x).

That is, the function f(x) is translated 5 units to the right and 1 unit upwards to get g(x).

Thus, the graph of g(x) is shown below.

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If S = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} and A =
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Answer:

a) = {0, 2, 3, 4, 5, 6, 8}, b = {0} empty set. c =  {0, 1, 6, 7, 8, 9} d =  {0, 1, 3, 5, 6, 7, 8, 9} e =  {0, 1, 5, 6, 7, 8, 9} f = {2,4} .

Step-by-step explanation:

Given:

S = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}

A =  {0, 2, 4, 6, 8}

B = {1, 3, 5, 7, 9}

C = {2, 3, 4, 5}

D = {1, 6, 7}

Solution:

a) A∪C = A + C - A∩C

            = {0, 2, 4, 6, 8} + {2, 3, 4, 5} - {2, 4}

            = {0, 2, 2, 3, 4, 4, 5, 6, 8} -  {2, 4}

            = {0, 2, 3, 4, 5, 6, 8}

b)  A∩B = ?

A∪B = A + B -   A∩B

A∪B +  A∩B = A + B

A∩B =  A + B - A∪B

        =   {0, 2, 4, 6, 8} +  {1, 3, 5, 7, 9} -   {0, 1, 2, 3, 4, 5, 6, 8, 9}

        = {0,1, 2, 3, 4, 5, 6,7, 8, 9} - {0, 1, 2, 3, 4, 5, 6, 8, 9}

A∩B = {0} empty set.

c) C′ = S - C

       = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} -  {2, 3, 4, 5}

       = {0, 1, 6, 7, 8, 9}

d) (C′∩D)∪B = ?

(C′∩D) = {0, 1, 6, 7, 8, 9} ∩ {1, 6, 7}

           = {1, 6, 7}

B =  {1, 3, 5, 7, 9}

(C′∩D)∪B = (C′∩D) + B - (C′∩D)∩B

                = {0, 1, 6, 7, 8, 9} +  {1, 3, 5, 7, 9} -  {1, 7, 9,}

                = {0, 1, 1, 3, 5, 6, 7, 7, 8, 9, 9} -  {1, 7, 9,}

                = {0, 1, 3, 5, 6, 7, 8, 9}

e) (S∩C)′ = S - (S∩C)′

(S∩C) =  {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} ∩ {2, 3, 4, 5}

              = {2, 3, 4, 5}

(S∩C)′ = S -  (S∩C)

           =  {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} -  {2, 3, 4, 5}

           =   {0, 1, 5, 6, 7, 8, 9}

f) A∩C∩D′ = ?

D′ = S - D

   = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} - {1, 6, 7}

   = {0, 2, 3, 4, 5, 8, 9}

A∩C∩D′ = {0, 2, 4, 6, 8} ∩  {2, 3, 4, 5} ∩ {0, 2, 3, 4, 5, 8, 9}

              =  {2,4}

       

       

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Answer:

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Step-by-step explanation:

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