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2 years ago

Help me in number 7 8 9 10 11 12 13 14

Mathematics

2 answers:

Zanzabum2 years ago

8 0

For number 7, you need to find out what number was multiplied by 5 to get 15, which would be 3. So, you multiply the numerator by 3 as well and you will have the missing number.
2/5=6/15

The least common multiple of two numbers is the smallest number that is a multiple of both numbers, that is not zero.
So, you need to find the smallest number that both 14 and 18 can be divided by.
The answer would be 126.

9 goes into 36 4 times, because 9x4=36. Because of this, you multiply the numerator by 4 as well. 4x5=20.
So, 5/9=20/36

The least common multiple of 5 and 10 would be 10, obviously. It isn't zero, and both 5 and 10 can be divided by 10.

The least common multiple of 42 and 36 is 252.

Three common multiples of 5 and 6. Look at the choices and choose the one where all three numbers can be divided by both 5 and 6.
30/6=5 and 30/5=6, 60/5=12 and 60/6=10, 90/5=18 and 90/6=15.
So, the answer is choice B.

The least common multiple of 30 and 60 is 60. 30 is half of 60, so we already know that 60 can be divided by 30. 60 can be divided by itself as well.

Well, divide each new denominator by 14, and then multiply that number by 9. If the number you get matches the numerator in the choice's fraction, then you found your answer.

Marina CMI [18]2 years ago

3 0

7 is A 8 is A 9 is D 10 is A 11 is

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El precio total por 3 1/2 kg de jitomate que compró Juana es 127.75

Para saber el precio total de los 3 1/2 kg de jitomate que compró Juana debemos hacer el siguiente procedimiento.

Necesitamos saber cuánto vale medio kg de jitomate, para ello dividimos 36.50 en 2.

36.50/2 = 18.25

Luego multiplicamos 36.50 por 3, para saber cuánto valen 3 kg de jitomate.

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Lia must work at least 5 hours per week in her family’s restaurant for $8 per hour. She also does yard work for $12 per hour. Li

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Answer:

(a)

$r\geq 5$

$r+y\leq 15$

$8r+12y\geq 120$

$y\geq 0$

(c)Maximum number of hours Lia can work at the restaurant and still meet her earnings goal = 15 hours

(d)Maximum Earning = $160

Step-by-step explanation:

Let r be the number of hours worked at the restaurant.

Let y be the number of hours of yard work,

Lia must work at least 5 hours per week in her family’s restaurant for $8 per hour.

$r\geq 5$

Since she does yard work, $y\geq 0$

Lia’s parents allow her to work a maximum of 15 hours per week overall.

$r+y\leq 15$

Lia’s goal is to earn at least $120 per week.

The restaurant, r pays $8 per hour

Yard work, y pays $12 per hour.

Therefore:

$8r+12y\geq 120$

The system of inequalities that represent this problem is therefore:

$r\geq 5$

$r+y\leq 15$

$8r+12y\geq 120$

$y\geq 0$

(b)The graph of the inequality is attached below

(c)When the graph is plotted, the vertices of the feasible region are:

(5,10)
(5, 6.7)
(15,0)

Where the first term is for the number of hours worked in the restaurant.

The maximum value of r possible is 15 from the three points.

Therefore, she can work at the restaurant for 15 hours and still meet her earning goal.

(d)Maximum Amount Lia can earn in 1 Week

At (5,10), Earning=(5X8)+(10X12)=40+120=$160

At (5, 6.7), Earning=(5X8)+(6.7X12)=40+80.4=$120.4
At (15,0) Earning=(15X8)+(0X12)=$120

Since she has to work at least 5 hours at the restaurant, the maximum amount possible is $160.

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