D=event that chip selected is defective
d=event that chip selected is NOT defective
Four possible scenarios for the first two selections:
P(DDD)=15/100*14/99*13/98=13/4620
P(DdD)=15/100*85/99*14/98=17/924
P(dDD)=85/100*15/99*14/99=17/924
P(ddD)=85/100*84/99*15/98=17/154
Probability of third selection being defective is the sum of all cases,
P(XXD)=P(DDD)+P(DdD)+P(dDD)+P(ddD)
=3/20
Pretty sure it's 10 liters to every 3 min. (10:3 or 10 over 3)
i got u fam
The information about the rational numbers and integers shows that the correct option is C.
<h3>How to explain the information?</h3>
It should be noted that rational numbers are numbers where we can write as a fraction of two integers. Any rational number is in the form a/b where a,b are integers and b is nonzero.
Terminating decimals can be written as a rational number. Something like 3.1 is equivalent to 31/10.
Of the four answer choices, only choice C is correct.
Choice A has the value '3' as a rational number, but it doesn't have it in the set of integers as well. So that's why choice A is incorrect.
Choice B has -3.4 in the set of integers, which is not correct. Integers do not have any decimal portion. The same applies to choice D also. We can rule choices B and D out.
Therefore, the correct option is C.
Learn more about integers on:
brainly.com/question/17695139
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