Answer:
1
Step-by-step explanation:
4+(-5*-1)-8
4+5-8
9-8
pemdas
Answer: 4.6 horas.
Step-by-step explanation:
Podemos calcular el tiempo necesario por una llave:
si sabemos que se llena en 8 horas con 4 llaves, entonces una sola llave va a tardar 4 veces 8 horas en llenar el tinaco, es decir, una sola llave tarda:
4*8h = 32 horas
ahora, si usamos 7 llaves, el tiempo necesario va a ser un septimo de eso:
(32 h por llave)/(7 llaves) = 32/7 horas = 4.6 horas.
Answer:
3x^2 + 3 --> 6, 15, 30, 51
2x^2 - 1 --> 1, 7, 17, 31
x^2 + 2 --> 3, 6, 11, 18
Step-by-step explanation:
Let's start with the first equation; 3x^2 + 3
Substitute 1 (the first digit in a sequence) for x.
3(1^2) + 3
3(1) + 3
3 + 3 = <u>6</u>
3(2^2) + 3 Then the second digit.
3(4) + 3
12 + 3 = <u>15</u>
Since the two numbers we have so far are 6 and 15, there is only one sequence this could match. 6, 15, 30, 51.
2(1^2) - 1
2(1) - 1
2 - 1 = <u>1</u>
This equation represents 1, 7, 17, 31.
These same steps apply to the other equation as well.
1^2 + 2, then 2^2 + 2, then 2^2 + 2, and so on. (But we don't need to do extra work to figure that out.)
600×3.5%=21. As a result, there are 21 phones that likely to be defective. Hope it help!
Answer:
Example 0-30 in 0-5 5-10 10-15 etc... upto 25-30
a) 12 and 15 or 10 and 15
b) none
c) none
a) Confidence Level Margin of Error Error Bar
68.3%, sx 12.2857 ±2.275 (±18.52%)
so a0 could be also 12.2857 - 2.275 = 10
Answer therefore may be 10 and 15
So try do a histogram go in 10's across 1-10,10-20,20-30,30-40,40-50
And if mean is 43 then you would need to multiply everything inside box by 0.3 before you can start the y axes
questions like this start with 0 - 50
