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Triss [41]
3 years ago
6

WILL MARK BRAINLIEST ANSWER!!! PLEASE HELP!! ripe pear falls from a tree and lands on the ground. As it hit the ground, the pear

had a speed of 23 feet per second. Approximately how far up in the tree was the pear before it fell? Use the formula below and assume that the acceleration due to gravity is 32 feet per second.

Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
3 0

Answer:

13 feet

Step-by-step explanation:

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After demonstrating the procedure by algebraic means, the expression (2\sqrt[3]{12} )\cdot (3\sqrt[3]{2} ) <em>is equivalent to</em> 6\cdot \sqrt[3]{24}.

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After demonstrating the procedure by algebraic means, the expression (2\sqrt[3]{12} )\cdot (3\sqrt[3]{2} ) <em>is equivalent to</em> 6\cdot \sqrt[3]{24}.

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