x = 45°
Solution:
Given data:
Measure of larger arc = 152°
Measure of smaller arc = 62°
<em>If a tangent and a secant intersect at the exterior of a circle then the measure of angle formed is one-half the positive difference of the measures of the intercepted arcs.</em>
⇒ x = 45°
The value of x is 45°.
Answer:
(0, -5), (4, -2), (-16, -17)
Step-by-step explanation:
I attach your full question in the image below
The equation is
3x-4y-8=12
Which can be rewritten as
3x-4y =12 +8
3x-20 = 4y
y = (3/4)*x - 5
We need to check each individual case
(0,-5)
y = (3/4)*(0) - 5
y = -5
True
(4,-2)
y = (3/4)*(4) - 5
y = -2
True
(8,2)
y = (3/4)*(8) - 5
y = 1
False
(-16,-17)
y = (3/4)*(-16) - 5
y = -17
True
(-1,-8)
y = (3/4)*(-1) - 5
y = -23/4
False
(-40,-34)
y = (3/4)*(-40) - 5
y = -35
False
(0,-5) (4,-2) and (-16,-17) are the solutions
Answer:
Domain = ( -∞,∞), {x|x ∈ R}
Range (-∞,2], {y|y ≤ 2}
Vertex (h,k) = (6,2)
Step-by-step explanation:
(Domain / Range) The absolute value expression has a V shape. The range of a negative absolute value expression starts at its vertex and extends to negative infinity.
(Vertex) To find the x coordinate of the vertex, set the inside of the absolute value
x − 6 equal to 0 . In this case, x − 6 = 0 .
x−6=0
Add 6 to both sides of the equation.
x=6
Replace the variable x with 6 in the expression.
y=−1/3⋅|(6)−6|+2
Simplify−1/3⋅|(6)−6|+2.
y=2
The absolute value vertex is ( 6 , 2 ) .
(6,2)
Hope this helps
