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SIZIF [17.4K]
3 years ago
14

Evaluate. 2 -2 4 undefined

Mathematics
1 answer:
LiRa [457]3 years ago
8 0

Answer:

2

Step-by-step explanation:

We have to get the value of the expression of - ∛(- 8).

Now, we can write the expression as  

- ∛(- 8)  

=-\sqrt[3]{-8}

= -(-8)^{\frac{1}{3} } {Converting into exponent form}

= -[(-2)^{3} ]^{\frac{1 }{3} } {Since (- 2) × (- 2) × (- 2) = - 8}

= - [(-2)^{3\times \frac{1}{3} } ]{Since we know that  [x^{a}] ^{b} = x^{ab}}

= - [- 2]

= 2 (Answer)

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To solve n+7=15 you should first
sertanlavr [38]

Answer:

  1. Collect like terms and simplify
  2. Subtract 7 from both sides

Step-by-step explanation:

METHOD 1

n+7=15\\n =15-7\\n = 8

METHOD 2

n+7-7=15-7\\n =8

7 0
3 years ago
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Find (x - 6)2
Sever21 [200]
Its 4-6=2 its easy because just keep useing numbers until the become two


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Elsa's magic wand can cast 53 spells. Her wand can cast 17fewer spells than her sister Anna's wand, which is a little bigger and
Mademuasel [1]

Answer:

<em> Anna's wand can cast 70 spells</em>

<em></em>

Step-by-step explanation:

Elsa's wand can cast 53 spells

her wand casts 17 fewer cells than her sister Anna's

Amount of spells cast by Anna's wand = ?

We write the question down in the form of an equation

x - 17 = 53

where x is the amount of spells Anna's wand can cast.

we then proceed to solve by collecting like terms to different sides of the equation. We'll have

x = 53 + 17

which leaves us with

x = 70

This means that<em> Anna's wand can cast 70 spells.</em>

4 0
3 years ago
Please help really quick I really need some help with this question
Marta_Voda [28]

Answer:

first two because they align almost perfectly with the scatterplot and fit the direction described

Step-by-step explanation:

8 0
2 years ago
Annual starting salaries for college graduates with degrees in business administration are generally expected to be between $10,
Andreyy89

Answer:

1) the planning value for the population standard deviation is 10,000

2)

a) Margin of error E = 500, n = 1536.64 ≈ 1537

b) Margin of error E = 200, n = 9604

c) Margin of error E = 100, n = 38416

3)

As we can see, sample size corresponding to margin of error of $100 is too large and may not be feasible.

Hence, I will not recommend trying to obtain the $100 margin of error in the present case.

Step-by-step explanation:

Given the data in the question;

1) Planning Value for the population standard deviation will be;

⇒ ( 50,000 - 10,000 ) / 4

= 40,000 / 4

σ = 10,000

Hence, the planning value for the population standard deviation is 10,000

2) how large a sample should be taken if the desired margin of error is;

we know that, n = [ (z_{\alpha /2 × σ ) / E ]²

given that confidence level = 95%, so z_{\alpha /2  = 1.96

Now,

a) Margin of error E = 500

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 500 ]²

n = [ 19600 / 500 ]²

n = 1536.64 ≈ 1537

b) Margin of error E = 200

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 200 ]²

n = [ 19600 / 200 ]²

n = 9604

c)  Margin of error E = 100

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 100 ]²

n = [ 19600 / 100 ]²

n = 38416

3) Would you recommend trying to obtain the $100 margin of error?

As we can see, sample size corresponding to margin of error of $100 is too large and may not be feasible.

Hence, I will not recommend trying to obtain the $100 margin of error in the present case.

7 0
2 years ago
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