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3 years ago

What is the solution for 2x + 3

Mathematics

1 answer:

Leokris [45]3 years ago

3 0

Answer:

Step-by-step explanation:

you would add the numbers like this 2+3 and that equals 5 but you have to keep the X because theres not another number to combine the 2x with

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Find the greatest common factor of the pair of numbers. 312 and 444

Andrews [41]

$312|2\\156|2\\.\ 78|2\\.\ 39|3\\.\ 13|13\\.\ \ 1|\\312=\fbox2\cdot\fbox2\cdot2\cdot\fbox3\cdot13$

$444|2\\222|2\\111|3\\.\ 37|37\\.\ \ \ 1|\\444=\fbox2\cdot\fbox2\cdot\fbox3\cdot37\\\\Therefore\ GCF(312;\ 444)=\fbox2\cdot\fbox2\cdot\fbox3=\boxed{\boxed{12}}$

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3 years ago

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Penicillin is ordered for a child weighing 35 pounds. The average dose for an adult is 360 mg. The child will receive ________ m

Gennadij [26K]

Penicillin is ordered for a child weighing 35 pounds. The average dose for an adult is 360 mg. The child will receive 210 mg. This is an approximation and the doctor has a final say on the dosage. The dosage is fixed based on the body weight and it varies from 3 to 6 mg per pound of body weight. I hope it helps you.

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3 years ago

A trapezoid and an isosceles trapezoid have different area formulas. True False

adelina 88 [10]

Answer:

false

Step-by-step explanation:

because its the top and bottom that are parallel, not the sides

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3 years ago

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14.50 increased by 7 percent equals?

Andrew [12]

14.50 * 7% = 1.015
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4 years ago

In response to the increasing weight of airline passengers, the Federal Aviation Administration (FAA) in 2003 told airlines to a

aleksandr82 [10.1K]

Answer:

There is a 33.72% probability that the total weight of the passengers exceeds 4500 pounds.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

There are 22 passengers. Passengers average 190 pounds in the summer, including clothing and carry-on baggage. But passengers vary, and the FAA did not specify a standard deviation. A reasonable standard deviation is 35 pounds. This means that $\mu = 22*190 = 4180, \sigma = 22*35 = 770$ .

What is the approximate probability that the total weight of the passengers exceeds 4500 pounds?

This probability is 1 subtracted by the pvalue of Z when $X = 4500$ . So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{4500 - 4180}{770}$

$Z = 0.42$

$Z = 0.42$ has a pvalue of 0.6628.

This means that there is a 1-0.6628 = 0.3372 = 33.72% probability that the total weight of the passengers exceeds 4500 pounds.

7 0

3 years ago