What is the solution for 2x + 3

Mathematics

1 answer:

Leokris [45]2 years ago

3 0

Answer:

Step-by-step explanation:

you would add the numbers like this 2+3 and that equals 5 but you have to keep the X because theres not another number to combine the 2x with

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a music store has 40 trumpets 39 clarinets 24 violins 51 fluites and 16 trambones in stock write each ratio in simplest gorm

disa [49]

Given:

A music store has the following:

40 trumpets

39 clarinets

24 violins

51 flutes

16 trombones

We will write the following ratios:

trumpets to violins =

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6 0

1 year ago

What is the sum of the infinite geometric series 9−6+4−83+...9-6+4-83+...??

vivado [14]

Successive terms have a common factor of $-\dfrac23$ , which means the $n$ th partial sum of the series can be written as

$S_n=9-6+4-\dfrac83+\cdots+9\left(-\dfrac23\right)^{n-1}$
$S_n=9\left(1+\left(-\dfrac23\right)^1+\left(-\dfrac23\right)^2+\left(-\dfrac23\right)^3+\cdots+\left(-\dfrac23\right)^{n-1}$

$\implies-\dfrac23S_n=9\left(\left(-\dfrac23\right)^1+\left(-\dfrac23\right)^2+\left(-\dfrac23\right)^3+\left(-\dfrac23\right)^4+\cdots+\left(-\dfrac23\right)^n\right)$

$\implies S_n-\left(-\dfrac23\right)S_n=9\left(1-\left(-\dfrac23\right)^n\right)$
$\dfrac53S_n=9\left(1-\left(-\dfrac23\right)^n\right)$
$S_n=\dfrac{27}5\left(1-\left(-\dfrac23\right)^n\right)$

As $n\to\infty$ , the geometric term vanishes, leaving you with

$S=\displaystyle\lim_{n\to\infty}S_n=\dfrac{27}5$