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olga nikolaevna [1]
4 years ago
10

Lena found the greatest common factor (GCF) of 24ab2c3 and 30a2b3c2 to be 6abc2 by using these steps:

Mathematics
1 answer:
AlladinOne [14]4 years ago
8 0
I believe the answer is B.
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belka [17]

sorry, i dont understand i need more information on this is there any other directions???

3 0
4 years ago
This oblique circular cone has radius of 5m and a hight of 6m what is the volume of the figure
trasher [3.6K]
Volume = 1/3(area of base) times height. 1/3(PI X R(squared)) X height. 1/3 x 3.14 x 25 x 6 = 157
7 0
3 years ago
Please help, I'm struggling with this so much! (8n^5-3n^4-56n^2+13n)÷(8n-3)
OlgaM077 [116]

Automatically, we can factor an n out of the dividend, as each term shares this factor.

The new dividend is 8n^4 - 3n^3 - 56n + 13

After applying algebraic long division, which is included in the screenshot below, the quotient is equal to n(n^3 - 7 + (8/8n - 3))

8 0
3 years ago
If T (n) =3n-1 what is the 3rd term
Stels [109]
The sequence is given by the formula T(n)=3n-1, where n is the value of the n'th term in the sequence.

Thus, 

T(1) calculates the value of the 1st term

T(2) calculates the value of the 2nd term

T(3) calculates the value of the 3rd term
.
.
an so on


the value of the third term is T(3)=3*3-1=9-1=8



Answer: 8
4 0
4 years ago
Elizabeth performed the geometric construction shown in the diagram. Based on her construction markings we can conclude that the
Alexeev081 [22]

Answer:

A- a regular hexagon

Step-by-step explanation:

5 0
3 years ago
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