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2 years ago

Write an

Mathematics

1 answer:

Helga [31]2 years ago

6 0

Answer:

Since the Line is Perpendicular

m.m'=-1

The line

y=x+8

Comparing with

Y=mx + C

m=1

m.m'=-1

m'=-1/m = -1/1 = -1.

y-y' = m'(x-x')

The point it passes is (-7,8)

y-8= -1(x--7)

y-8=-1(x+7)

y-8 = -x - 7

y + x -1 = 0.

or In Slope intercept Form

Just Make y the subject

y= -x + 1 ..... This is your answer.

Hope this helps!!!

You might be interested in

A new operation is defined by a△b=a^2-b/b-a^2. 4△3.

dmitriy555 [2]

As the new mathematical operation is defined by a△b=a^2-b/b-a^2, the value of 4△3 using the same operation will be 4△3 = -1

As per the question statement, we are given a new mathematical operation a△b=a^2-b/b-a^2 and we are supposed to find the value of 4△3 using the same operation.

Given, a△b=a^2-b/b-a^2

now 4△3 = (4^2-3) / (3-4^2)

4△3 = (16-3) / (3-16)

4△3 = 13 / -13

4△3 = -1

Hence, as the new mathematical operation is defined by a△b=a^2-b/b-a^2, the value of 4△3 using the same operation will be 4△3 = -1.

Mathematical operation: An operator in mathematics is often a mapping or function that transforms components of one space into elements of another.

To learn more about mathematical operation, click on the link given below:

brainly.com/question/8959976

#SPJ1

8 0

1 year ago

7.Sandy has a total of 35 coins in her money jar. If Sandy's jar contains only nickels and dimes and the value of all the coins

Mademuasel [1]

Answer: 35

Step-by-step explanation:

Let the number of nickels be x

Then the number of dimes, using

ONE PART = TOTAL MINUS OTHER PART,

is 35-x. ( hope this helps have a good day/night :) )

7 0

2 years ago

6.81 is what percent of 45.5

frosja888 [35]

To get the solution, we are looking for, we need to point out what we know.

1. We assume, that the number 45.5 is 100% - because it's the output value of the task.

2. We assume, that x is the value we are looking for.

3. If 45.5 is 100%, so we can write it down as 45.5=100%.

4. We know, that x is 6.81% of the output value, so we can write it down as x=6.81%.

5. Now we have two simple equations:

1) 45.5=100%

2) x=6.81%

where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:

45.5/x=100%/6.81%

6. Now we just have to solve the simple equation, and we will get the solution we are looking for.

7. Solution for what is 6.81% of 45.5

45.5/x=100/6.81

(45.5/x)*x=(100/6.81)*x - we multiply both sides of the equation by x

45.5=14.684287812041*x - we divide both sides of the equation by (14.684287812041) to get x

45.5/14.684287812041=x

3.09855=x

x=3.09855

now we have:

6.81% of 45.5=3.09855

Hope this helps!

4 0

3 years ago

Read 2 more answers

Find T5(x) : Taylor polynomial of degree 5 of the function f(x)=cos(x) at a=0 . (You need to enter function.) T5(x)= Find all va

Burka [1]

Answer:

$\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}$

The polynomial is an approximation with an error less than or equals to 0.002652 for x in the interval

[-1.113826815, 1.113826815]

Step-by-step explanation:

According to Taylor's theorem

$\bf f(x)=f(0)+f'(0)x+f''(0)\displaystyle\frac{x^2}{2}+f^{(3)}(0)\displaystyle\frac{x^3}{3!}+f^{(4)}(0)\displaystyle\frac{x^4}{4!}+f^{(5)}(0)\displaystyle\frac{x^5}{5!}+R_6(x)$

with

$\bf R_6(x)=f^{(6)}(c)\displaystyle\frac{x^6}{6!}$

for some c in the interval (-x, x)

In the particular case f

f(x)=cos(x)

we have

$\bf f'(x)=-sin(x)\\f''(x)=-cos(x)\\f^{(3)}(x)=sin(x)\\f^{(4)}(x)=cos(x)\\f^{(5)}(x)=-sin(x)\\f^{(6)}(x)=-cos(x)$

therefore

$\bf f'(x)=-sin(0)=0\\f''(0)=-cos(0)=-1\\f^{(3)}(0)=sin(0)=0\\f^{(4)}(0)=cos(0)=1\\f^{(5)}(0)=-sin(0)=0$

and the polynomial approximation of T5(x) of cos(x) would be

$\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}$

In order to find all the values of x for which this approximation is within 0.002652 of the right answer, we notice that

$\bf R_6(x)=-cos(c)\displaystyle\frac{x^6}{6!}$

for some c in (-x,x). So

$\bf |R_6(x)|\leq|\displaystyle\frac{x^6}{6!}|=\displaystyle\frac{|x|^6}{6!}$

and we must find the values of x for which

$\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652$

Working this inequality out, we find

$\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652\Rightarrow |x|^6\leq1.90944\Rightarrow\\\\\Rightarrow |x|\leq\sqrt[6]{1.90944}\Rightarrow |x|\leq1.113826815$

Therefore the polynomial is an approximation with an error less than or equals to 0.002652 for x in the interval

[-1.113826815, 1.113826815]

8 0

3 years ago

3|3t+1|=2|6t+3| Need hep

mars1129 [50]

Answer:

your answer would be t=-1 or t=1

Step-by-step explanation:

-(2t-3) = 3t-2

Multiply

-2t+3 = 3t-2

Rearrange and Add up

-5t = -5

Divide both sides by 5

-t = -1

Multiply both sides by (-1)

t = 1

Which is the solution for the Negative Case

Solve the Positive Case

(2t-3) = 3t-2

Rearrange and Add up

-t = 1

Multiply both sides by (-1)

t = -1

have a great day!

4 0

3 years ago