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Solnce55 [7]
3 years ago
15

Jake had soccer practice for 2 hours last month. Jake practiced 8 times more this month . How many hours did Jake practice this

month?
Mathematics
1 answer:
Alja [10]3 years ago
3 0

Answer:

16 Hours your welcome

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111.25 is what percent of 89?​
leonid [27]

The answer is 125%

111.25/89 × 100 = 125%

Happy to help!

8 0
3 years ago
Read 2 more answers
Solve.and show your work
Marysya12 [62]

Answer:

a) x > − 24 \frac{3}{4}

b) x < − 3

c) q < 56

Step-by-step explanation:

a) −2/5x−9<9/10

<=> 2/5x + 9 > − 9/10

<=> 2/5x > − 9/10 − 9

<=> 2×2/2×5x > − 9/10 − 9×10/10

<=> 4/10x > − 99/10

<=> x > − 99/4

<=> x > − 24 \frac{3}{4}

b) 4x+6<−6

<=> 4x < − 6 − 6

<=> 4x < − 12

<=> x < − 12/4

<=> x < − 3

c) q+12−2(q−22)>0

<=> q+12−2q −2×(−22)>0

<=> (q−2q) + (12+ 44) >0

<=> −q + 56 >0

<=> q < 56

8 0
3 years ago
What is 0.00078 in scientific notation?
frozen [14]
Answer: 7.8 x 10^-4
4 0
3 years ago
Li is making beaded necklaces for each necklace, she uses 27 spacers, plus 5 beads per inch of necklace length. Write an equatio
brilliants [131]
Given that <span>Li is making beaded necklaces for each necklace, she uses 27 spacers, plus 5 beads per inch of necklace length.

The equation to find how many beads Li needs for each necklace can be obtained as follows:

A. The input variable is the number of inches of the necklace length (x).

B. The output variable is the number of beads Li needs for each necklace (y).

C. The required equation is given by

y = 5x</span>
6 0
3 years ago
At 12 noon, leslie recorded the temperature as 56 degrees f. The temperature had increased by 8 degrees f from 10am. The tempera
Marat540 [252]
Let the temperature at 10am be x, then
x + 8 = 56
x = 56 - 8 = 48 degrees F

Let y be the temperature at 8am, then
y - 2 = 48
y = 48 + 2 = 50 degrees.
4 0
3 years ago
Read 2 more answers
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