Answer:
D. f(x) exist for all real numbers where x ≤ -1 or x ≥ 1
Explanation:
You can't divide by 0 and
You can't have a negative squareroot.
So solve for when x=0 for the denominator,
and when is x<0 for the squareroot.
When I graduate, I am going to fine an awesome wife, a girl that loves me and I love her. I want to explore the world and have 1 kid.
~Jurgen
C
A is biased
B, some people may view the assignments as easy and it doesn’t show that it was more that last year
D doesn’t strongly support it
Shape is correct. This is because we're talking about the door being rectangular, it is (B).
I believe the answer is d.
