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il63 [147K]
3 years ago
6

Helloo! please quick help with this it’s super simple

Mathematics
2 answers:
lorasvet [3.4K]3 years ago
6 0

Answer:

1

Step-by-step explanation:

\bigg(3 {w}^{4}  {z}^{3} m \bigg) ^{0}  \\  =  {3}^{0}  \times {w}^{4 \times 0}  \times  {z}^{3 \times 0}  \times  {m}^{0}  \\ =  {3}^{0}  \times {w}^{0}  \times  {z}^{0}  \times  {m}^{0}  \\  = 1 \times 1 \times 1 \times 1.. ( \because {a}^{0 }  = 1) \\  = 1 \\  \therefore \:  \bigg(3 {w}^{4}  {z}^{3} m \bigg) ^{0}  = 1

NISA [10]3 years ago
6 0

Answer:

1

Step-by-step explanation:

whenever we have 0 in the exponent the term becomes equal to 1

(3w^4z^3m)^0

multiplying 0 with all terms inside the bracket

3^0 × w^4×0 × z^3×0 × m^1×0

solving the powers

3^0 × w^0 × z^0 × m^0

since we have 0 in the exponent so all the terms will become 1

1 × 1 × 1 × 1 = 1

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1) isolate y

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-4x -4x
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5

y = -4/5x + 60

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The slope is -4/5x + 60
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3 years ago
You are planning a party for all of your friends. The cost of renting a room is $35, cost of food per person is $4. How much wil
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Answer:

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In a U. S . Poll 8 out of 12 citizens said they were happy with the job Obama is doing. If 126 people were surveyed...
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Brrunno [24]

Answer:

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4 0
3 years ago
I need help with this problem
cupoosta [38]
\bf \begin{cases}
(n^4)^p=n^{12}\to &n^{4\cdot p}=n^{12}\to 4p=12
\\
&\qquad \uparrow \\
&\textit{same bases, thus}\\
&\qquad \downarrow 
\\
n^3\cdot n^q=n^6\to &n^{3+q}=n^6\to 3+q=6
\end{cases}
\\\\\\
thus\implies 
\begin{cases}
4p=12\implies p=\frac{12}{4}
\\\\
3+q=6\implies q=6-3
\end{cases}
\\\\

\\\\
then\implies p\cdot q=\boxed{?}
7 0
3 years ago
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