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Hunter-Best [27]

3 years ago

11

A new gym is being built at a local high school. The length of the gym on the blueprint is 12 inches. Find the actual length of

the gym if the scale of the blueprint is 0.75 inches is equal to 5 feet.
Since no one asked it yet, ¯\_(ツ)_/¯

1 answer:

djyliett [7]3 years ago

8 0

12÷.75=16
16 × 5ft=80 ft

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alekssr [168]

Convert percentages to units.
100% - 20% = 80% = 0.8
100% - 25% = 75% = 0.75

Then multiply those together:
0.8*0.75=0.6=60%

100% - 60% = 40%. That's the overall price percentage reduction.

P.S. You can convert percentages to units by diving % by 100 for example 100% divided by 100 is equal to 1.
And vice versa aka multiply units by 100 and you get %, for example 0.8 times 100 is 80%

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Convert 0.0002 ug to mg:<br> Please help

Ksju [112]

1 ug = 0,001 mg

0,0002 ug= x

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2 years ago

Noah manages a buffet at a local restaurant. He charges $10 for the buffet. On average, 16 customers choose the buffet as their

kicyunya [14]

Answer:

$3 max

Step-by-step explanation:

Charge= b, Customer= c, Revenue= r

r= bc, currently, r= 16*10= $160

We know that: b+1 ⇒ c-2 and the target is r ≥ 130

So, this will all be reflected as:

b=10+x ⇒ c= 16-2x

(10+x)(16-2x) ≥ 130
160 -20x +16x - 2x² ≥ 130
-2x² - 4x + 30 ≥ 0
x² + 2x -15 ≤ 0
(x+1)² ≤ 4²
x+1 ≤ 4 (negative value not considered)
x ≤ 3

As we see the max increase amount is $3, when the revenue will be:

(10+3)*(16-3*2)= 13*10= $130

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2 years ago

What is the slope equation? Drag and drop answers

zubka84 [21]

Answer:

y = 2x + 9

Step-by-step explanation:

The y-intercept: 9

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2 years ago

the height h(t) of a trianle is increasing at 2.5 cm/min, while it's area A(t) is also increasing at 4.7 cm2/min. at what rate i

nekit [7.7K]

Answer:

The base of the triangle decreases at a rate of 2.262 centimeters per minute.

Step-by-step explanation:

From Geometry we understand that area of triangle is determined by the following expression:

$A = \frac{1}{2}\cdot b\cdot h$ (Eq. 1)

Where:

$A$ - Area of the triangle, measured in square centimeters.

$b$ - Base of the triangle, measured in centimeters.

$h$ - Height of the triangle, measured in centimeters.

By Differential Calculus we deduce an expression for the rate of change of the area in time:

$\frac{dA}{dt} = \frac{1}{2}\cdot \frac{db}{dt}\cdot h + \frac{1}{2}\cdot b \cdot \frac{dh}{dt}$ (Eq. 2)

Where:

$\frac{dA}{dt}$ - Rate of change of area in time, measured in square centimeters per minute.

$\frac{db}{dt}$ - Rate of change of base in time, measured in centimeters per minute.

$\frac{dh}{dt}$ - Rate of change of height in time, measured in centimeters per minute.

Now we clear the rate of change of base in time within (Eq, 2):

$\frac{1}{2}\cdot\frac{db}{dt}\cdot h = \frac{dA}{dt}-\frac{1}{2}\cdot b\cdot \frac{dh}{dt}$

$\frac{db}{dt} = \frac{2}{h}\cdot \frac{dA}{dt} -\frac{b}{h}\cdot \frac{dh}{dt}$ (Eq. 3)

The base of the triangle can be found clearing respective variable within (Eq. 1):

$b = \frac{2\cdot A}{h}$

If we know that $A = 130\,cm^{2}$ , $h = 15\,cm$ , $\frac{dh}{dt} = 2.5\,\frac{cm}{min}$ and $\frac{dA}{dt} = 4.7\,\frac{cm^{2}}{min}$ , the rate of change of the base of the triangle in time is:

$b = \frac{2\cdot (130\,cm^{2})}{15\,cm}$

$b = 17.333\,cm$

$\frac{db}{dt} = \left(\frac{2}{15\,cm}\right)\cdot \left(4.7\,\frac{cm^{2}}{min} \right) -\left(\frac{17.333\,cm}{15\,cm} \right)\cdot \left(2.5\,\frac{cm}{min} \right)$

$\frac{db}{dt} = -2.262\,\frac{cm}{min}$

The base of the triangle decreases at a rate of 2.262 centimeters per minute.

6 0

2 years ago