2 years ago

A die is rolled twice. what is the probability of showing a 1 on the first roll and an even number on the second roll?

Mathematics

1 answer:

marta [7]2 years ago

4 0

The probability of it showing a 1 is 1/6 and the probability of it showing an even number on the second roll is 3/6.

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What is 65,789 rounded to the nearest ten thousand?

myrzilka [38]

Answer:

65789.000

Step-by-step explanation:

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2 years ago

Simplify the expression.<br><br> <img src="https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B1%2B%5Csqrt%7B3%7D%20%7D" id="TexFormula1" t

REY [17]

Answer:

Step-by-step explanation:

Rationalize the denominator by multiplying both denominator & numerator by the conjugate of the denominator.

Conjugate of the denominator 1 + √3 is 1 - √3

$\frac{6}{1+\sqrt{3}}=\frac{6(1-\sqrt{3})}{(1+\sqrt{3})(1-\sqrt{3})}\\\\=\frac{6(1-\sqrt{3})}{(1+\sqrt{3})(1-\sqrt{3})}\\\\=\frac{6(1-\sqrt{3})}{1^{2}-(\sqrt{3})^{2}}\\\\=\frac{6(1-\sqrt{3})}{1-3}\\\\=\frac{6(1-\sqrt{3})}{-2}\\\\=(-3)(1-\sqrt{3})\\\\=-3+3\sqrt{3}$