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posledela
3 years ago
12

Many pollutants from coal-fired power plants are properly managed today. Which of the following is currently considered to be th

e biggest threat to the environment? Many pollutants from coal-fired power plants are properly managed today. Which of the following is currently considered to be the biggest threat to the environment? carbon dioxide sulfur dioxide nitrous oxide oxygen methane gas
Chemistry
1 answer:
sammy [17]3 years ago
5 0

Answer:

Sulfur dioxide

Explanation:

Sulfur dioxide (SO₂) is a colorless gas, which comes from burning fossil fuels like burning coal, oil and diesel from vehicles. This gas is also released into the environment through volcanic eruptions.

Sulfur dioxide is considered one of the worst air pollutants, mainly because it accumulates in droplets in the air and also because it reacts with other compounds in the atmosphere, forming particulate materials.

This gas is a major contributor to the warming of the planet. Its presence in acid rain (which makes it return from the atmosphere to the earth) is dangerous for plants and animals, in addition to corroding some materials and affecting monuments, buildings, statues.

Acid rain generated by SO₂ and other compounds can lower the pH of lakes and reduce fish populations. In plants, vegetables and flowers, it compromises production and growth.

In humans, sulfur dioxide can cause acute and chronic health effects, especially on the respiratory system, in addition to aggravating cardiovascular problems due to the simultaneous presence of SO₂ and particles in the atmosphere.

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Cal is titrating 50.8 mL of 0.319 M HBr with 0.337 M Ba(OH)2. How many mL of Ba(OH)2 does Cal need to add to reach the equivalen
alexgriva [62]

Answer:

V_{base}=24.04mL

Explanation:

Hello!

In this case, according to the chemical reaction by which HBr reacts with Ba(OH)2:

2HBr+Ba(OH)_2\rightarrow BaBr_2+2H_2O

We can see there is a 2:1 mole ratio between the acid and the base; thus, at the equivalent point we can write:

2M_{base}V_{base}=M_{acid}V_{acid}

Therefore, for is to compute the volume of the used base, we proceed as shown below:

V_{base}=\frac{M_{acid}V_{acid}}{2M_{base}}

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Best regards!

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