<u>Answer:</u> Amount of iron produced is 101.36 grams.
<u>Explanation:</u>
For the reaction of aluminium and iron oxide, the equation follows:

By Stoichiometry of the reaction,
When 1 mole of aluminium oxide is produced, then 2 moles of iron is also produced.
So, when 0.905 moles of aluminium oxide is produced, then
of iron is also produced.
Now, to calculate the amount of iron produced, we use the equation:

Molar mass of iron = 56 g/mol
Moles of iron = 1.81 moles
Putting values in above equation, we get:

Hence, amount of iron produced is 101.36 grams.
Answer:
c = 0.25 j/g.°C
Explanation:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Given data:
Mass of metal = 50.0 g
Heat needed = 314 j
Initial temperature = 25°C
Final temperature = 50 °C
Specific heat = ?
Solution:
ΔT = 50 °C - 25°C = 25°C
Q = m.c. ΔT
c = Q / m. ΔT
c = 314 j / 50.0 g . 25°C
c = 314 j / 1250 g. °C
c = 0.25 j/g.°C
The volume of eye drop fluid in a bottle is specified in milliliter, because in medical 1 drop=12ml
Answer:
C. 101.2 L
Explanation:
N2 + H2= NH3
Balancing it,
N2 + 3 H2 = 2.NH3
(1 mol) (3 mol) (2 mol)
which means
1 molecule of nitrogen reacts with 3 molecule of hydrogen to form ammonia.
Likewise,
50.6 l of nitrogen reacts with 50.6 × 3= 151.8 l of hydrogrn to form 50.6 × 2= 101.2 l of ammonia.
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