What is the solution to 3 + 4e^x+1 = 11?
Solution:

To solve for x, Let us subtract 3 from both sides



Let us divide by 4 on both sides



Let us take ln on both sides

So, x+1=ln(2)
To solve for x, Let us subtract 1 from both sides
x+1-1=ln(2) -1
x+0=ln(2)-1
x= ln(2) -1
Answer: Option (A)
x=ln(2)-1
Answer:
Because of the minus sign
2 becomes - 2
The answer is -2
Multiply a and 7
Multiply a and 1
The a just gets copied along.
The answer is a
a
7*a evaluates to 7a
Multiply b and 4
Multiply b and 1
The b just gets copied along.
The answer is b
b
4*b evaluates to 4b
7*a+4*b evaluates to 7a+4b
Multiply -2 by 7a+4b
we multiply -2 by each term in 7a+4b term by term.
This is the distributive property of multiplication.
Multiply -2 and 7a
Multiply 1 and a
The a just gets copied along.
a
-2 × 7a = -14a
Multiply -2 and 4b
Multiply 1 and b
The b just gets copied along.
b
-2 × 4b = -8b
-2*(7*a+4*b) evaluates to -14a-8b
Multiply c and 6
Multiply c and 1
The c just gets copied along.
The answer is c
c
6*c evaluates to 6c
The answer is -14a-8b-6c
-2*(7*a+4*b)-6*c evaluates to -14a-8b-6c
The final answer is
-14a-8b-6c
Step-by-step explanation:
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Answer:
see explanation
Step-by-step explanation:
Note the common difference d between consecutive terms
d = 10 - 3 = 17 - 10 = 24 - 17 = 7
This means the sequence is arithmetic with n th term
= a₁ + (n - 1)d
Here a₁ = 3 and d = 7, thus explicit formula is
= 3 + 7(n - 1) = 3 + 7n - 7 = 7n - 4, thus
= (7 × 18) - 4 = 126 - 4 = 122
Answer:
the awnser is A
Step-by-step explanation:
9x=6x+3
x=1
9(1)