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4 years ago

Okay I been on these 2 questions for about 30 min and I can't figure it out.

1 answer:

5 0

For #1 you have one leg of a right triangle measuring 4000 (the height of the mountain) and the other leg is 3000 (the distance that Mario is from Jenna). The angle of elevation is the one on the base of the triangle across from the right angle. To find the measure of the angle, use the tangent ratio: tan(A)=4000/3000, which could be simplified to tanA = 4/3. Do that on your calculator using the inverse tangent function to get that the angle of elevation from Mario to Jenna is 53 degrees.
For #2 you have another right triangle situation where the length of the hypotenuse is 20 and the base leg is 10. You are finding again the base angle across from the right angle. Use the cosA=10/20, aka cosA=.5. Again use the inverse cos function on your calculator to find the angle in question is 60 degrees.

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Solve the following system of equations. Enter the y-coordinate of the solution. Round your answer to the nearest tenth.

ankoles [38]

Lets try substitution5x+2y=21=5x=21-2y=x=(21-2y)/5

sub into second equation

-2(21-2y)/5+6y=-34(-42+4y)/5+6y=-34solve for yy=-64/17plug into equation and solve for x=(97/17)

7 0

3 years ago

Read 2 more answers

1 point

vesna_86 [32]

The answer is A 1/4=X/64

8 0

3 years ago

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The probability that a randomly selected 2 2-year-old male garter snake garter snake will live to be 3 3 years old is 0.98861 0

Mnenie [13.5K]

Answer:

a. $Probability = 0.97735$

b. $Probability = 0.92294$

c. $P(At\ Least\ One) = 1$

No, it is not unusual if at least 1 lives up to 3.

Step-by-step explanation:

Given

Represent the probability that a 2 year old snake will live to 3 with P(Live);

$P(Live) = 0.98861$

Solving (a): Probability that two selected will live to 3 years.

Both snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

$Probability = P(Live)\ and\ P(Live)$

$Probability = 0.98861 * 0.98861$

$Probability = 0.9773497321$

$Probability = 0.97735$ <em>--- Approximated</em>

Solving (b): Probability that seven selected will live to 3 years.

All 7 snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

$Probability = P(Live)^n$

Where $n = 7$

$Probability = 0.98861^7$

$Probability = 0.92294324145$

$Probability = 0.92294$ <em>--- Approximated</em>

Solving (c): Probability that at least one of seven selected will not live to 3 years.

In probabilities, the following relationship exist:

$P(At\ Least\ One) = 1 - P(None).$

So, first we need to calculate the probability that none of the 7 lived up to 3.

If the probability that one lived up to 3 years is 0.98861, then the probability than one do not live up to 3 years is 1 - 0.98861

This gives:

$P(Not\ Live) = 0.01139$

The probability that none of the 7 lives up to 3 is:

$P(None) = P(Not\ Live)^7$

$P(None) = 0.01139^7$

Substitute this value for P(None) in

$P(At\ Least\ One) = 1 - P(None).$

$P(At\ Least\ One) = 1 - 0.01139^7$

$P(At\ Least\ One) = 0.99999999999997513055642436060443621$

$P(At\ Least\ One) = 1$ ---- Approximated

No, it is not unusual if at least 1 lives up to 3.

This is so because the above results, which is 1 shows that it is very likely for at least one of the seven to live up to 3 years

7 0

3 years ago

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Goshia [24]

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In object that weighs 1 pound on earth on the weighs 0.17 pound on the moon Zacks dog weighs 17 1/2 pounds on earth how much mor

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I'm sorry idk 7 pounds

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3 years ago