Given:
PQRS is a circle, PQT and SRT are straight lines.
To find:
The value of x.
Solution:
Since PQRS is a circle, PQT and SRT are straight lines, therefore, PQRS isa cyclic quadrilateral.
We know that, sum of opposite angles of a cyclic quadrilateral is 180 degrees.
Now, SRT is a straight line.
(Linear pair)
...(i)
According to the Exterior angle theorem, in a triangle the measure of an exterior angle is equal the sum of the opposite interior angles.
Using exterior angle theorem in triangle QRT, we get
Therefore, the value of x is 103 degrees.
Answer: a. p = c/5 - 43 b. 17 people
Step-by-step explanation:
c= 5p + 215
A) a said solve for p so we will solve for p in the equation.
c= 5p + 215 First Subtract 215 from both sides
-215 -215
c - 215 = 5p Now divide both sides by 5.
p = c/5 - 43
B) If c is the total cost of hosting a birthday party then we will input 300 into the equation for c and solve for p.
300 = 5p + 215 First subtract 215 from both sides
-215 -215
85 = 5p Divide both sides by 5
p = 17
This means 17 people can attend the meeting if Allies parents are willing to spend $300.
Assume if it is cloudy, then you are outside.
I have done this question before but i can’t remember
Answer:
58.1 cm
Step-by-step explanation:
The length of each support rod can be found using the Pythagorean theorem. The geometry can be modeled by a right triangle, such that the distance from centre is one leg and half the length of the rod is the other leg of a triangle with hypotenuse equal to the radius of the grill.
__
<h3>Pythagorean theorem</h3>
The theorem tells us that the sum of the squares of the legs of a right triangle is the square of the hypotenuse. For legs a, b and hypotenuse c, this is ...
c² = a² +b²
<h3>application</h3>
For the geometry of the grill, we can define a=7.5 and c=30. Then b will be half the length of the support rod.
30² = 7.5 +b²
b² = 900 -56.25 = 843.75
b = √843.75 ≈ 29.0473
The length of each support rod is twice this value, so ...
rod length = 2b = 2(29.0473) = 58.0947
Each support rod is about 58.1 cm long.
