People need to start making the points a bigger value
Answer:
a. v(t)= -6.78 + 16.33 b. 16.33 m/s
Step-by-step explanation:
The differential equation for the motion is given by mv' = mg - γv. We re-write as mv' + γv = mg ⇒ v' + γv/m = g. ⇒ v' + kv = g. where k = γ/m.Since this is a linear first order differential equation, We find the integrating factor μ(t)= =. We now multiply both sides of the equation by the integrating factor.
μv' + μkv = μg ⇒ v' + kv = g ⇒ [v]' = g. Integrating, we have
∫ [v]' = ∫g
v = + c
v(t)= + c.
From our initial conditions, v(0) = 9.55 m/s, t = 0 , g = 9.8 m/s², γ = 9 kg/s , m = 15 kg. k = y/m. Substituting these values, we have
9.55 = 9.8 × 15/9 + c = 16.33 + c
c = 9.55 -16.33 = -6.78.
So, v(t)= 16.33 - 6.78. m/s = - 6.78 + 16.33 m/s
b. Velocity of object at time t = 0.5
At t = 0.5, v = - 6.78 + 16.33 m/s = 16.328 m/s ≅ 16.33 m/s
X=-2 not 2.
EXPLANATION:
x-2y=12
-3x+y=-1
x-2y=12
2(-3x+y)=-1
x-2y=12
-6x+2y=-2
-5x=10
5x/-5=10/-5
x=-2
Step-by-step explanation:
<u>The graph of a system of parallel lines will have no solutions. </u>
Because they will never intersect, having same slopes.
=========================
<u>The graph of a system of equations with different slopes will have no solutions. </u>
Because they will intersect exactly once, having different slopes.