This question is super easy.


Hope this helps!
Thanks!
-Charlie
Answer:
<h2>1.04</h2>
Step-by-step explanation:
<h2>Hope this helps. Mark as brainlest plz!</h2>
Answer:

Step-by-step explanation:
First, you need to divide everything by 6.
Then you put everything in a radical to get this:

Answer:

Step-by-step explanation:
Given


See attachment for prism
Required
Find x
The prism has a regular hexagon base
The base area is calculated as:

This gives:




Side x represents the height.
So, we have:

Make x the subject




--- approximated
Answer:
The arrangements of things following one after another in time