Replace <span><span>f<span>(x)</span></span><span>fx</span></span> with <span>yy</span>.<span><span>y=<span><span>6<span>x3</span></span><span>−8</span></span></span><span>y=<span><span>6<span>x3</span></span><span>-8</span></span></span></span>Interchange the variables.<span><span>x=<span><span>6<span>y3</span></span><span>−8</span></span></span><span>x=<span><span>6<span>y3</span></span><span>-8</span></span></span></span>Solve for <span>yy</span>.
<span><span>y=<span><span>3<span>√<span>36<span>(<span>x+8</span>)</span></span></span></span>6</span></span><span>y=<span><span><span>36<span>x+8</span></span>3</span>6</span></span></span>Solve for <span>yy</span> and replace with <span><span><span>f<span>−1</span></span><span>(x)</span></span><span><span>f<span>-1</span></span>x</span></span>.
<span><span><span>f<span>−1</span></span><span>(x)</span></span>=<span><span>3<span>√<span>36<span>(<span>x+8</span>)</span></span></span></span><span>6</span></span></span>
Given:

where, f(x) is the amount of a 12-mg dose of antibiotic left in her bloodstream after x hours.
To find:
The remaining mg in her bloodstream after 2 hours.
Solution:
The amount of a 12-mg dose of antibiotic left in her bloodstream after x hours is represented by the function

Putting x=2, we get the remaining mg in her bloodstream after 2 hours.



Therefore, the remaining mg in her bloodstream after 2 hours is 8.0688 mg.
Answer:

Step-by-step explanation:

4•7=28
4•-x=-4x
28-4x
In standard form, you always put the number with the variable first in the equation.
Answer: -4x+28
Answer:
19.634954085
Step-by-step explanation:
Pipe Diameter = Height of the trench
Pipe Height = Width of the trench
V = Pi*r^2*L/ Pi*r^2*h
= 22/7 x (2.5/2)^2 x 4
= 19.634954085