Answer:
Step-by-step explanation:
If y = 2x + 1, then dy/dt = 2(dx/dt).
If y = 2x + 1, then y = 2(40) + 1 when 40 is substituted for x. y = 81.
(a) if dx/dt = 3, find dy/dt when x = 4:
Replacing dx/dt with 3 in dy/dt = 2(dx/dt) yields dy/dt = 2(3) = 6.
(b) if dy/dt = 2, find dx/dt when x = 40:
Replacing dy/dt with 2 in dy/dt = 2(dx/dt) results in 2 = 2(dx/dt), so dx/dt must be 1.
X = smaller number, y = larger number
x + y = 15.....x = 15 - y
4x = 2y - 60
4(15 - y) = 2y - 60
60 - 4y = 2y - 60
60 + 60 = 2y + 4y
120 = 6y
120/6 = y
20 = y <==== larger number is 20
x + y = 15
x + 20 = 15
x = 15 - 20
x = - 5
Answer:
16x²+6x+3
Step-by-step explanation:
x²+6x+3(5x²-4)+15
x²+6x+15x²-12 +15
16x²+6x+3