Some racquet balls are sold in cylindrical cans of three balls. Each ball has a diameter of 2.25 inches. The can has a diameter
of 2.25 inches and is 6.75 inches tall. Find the volume of the empty space in the can. Use 3.14 for p. Round to the nearest hundredth.
2 answers:
1) Volume of each ball: [4/3]π(r^3) = [4/3]π(2.25/2)^3 = 5.96 in^3
2) Volume of 3 balss: 3*5.96 in^3 = 17.88 in^3
3) Volumen of the cylindrical can: [πr^2]h = π(2.25/2)^2 * 6.75 = 26.82 in^3
4) Empty space: 26.82 in^3 - 17.88 in^3 = 8.94 in^3
Answer:
Volume of the empty space = 6.95
= 7 (approx.)
Step-by-step explanation:
Volume of three spherical balls,
V =
Volume of the can, V =
V =
V = 24.83
Therefore, volume of the empty space = Volume of the can - volume of the three balls
= 24.83 - 17.88
= 6.95
= 7 (approx.)
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