The answer should be the third one I believe
Answer:
y=x+3
(0,3)(1,4)
y=x+2
(0,2)(1,3)
Step-by-step explanation:
- For Y=X+3 it could be any point for Y as long as X is 3 less than Y.
- For Y=X+3 it could be any point for X and long as Y is 3 more than X.
- For Y=X+2 it could be any point for Y as long as X is 2 less than Y.
- For Y=X+2 it could be any point for X and long as Y is 2 more than X.
Answer:
The point C is 12.68 km away from the point A on a bearing of S23.23°W.
Step-by-step explanation:
Given that AB is 50 km and BC is 40 km as shown in the figure.
From the figure, the length of x-component of AC = |AB sin 80° - BC cos 20°|
=|50 sin 80° - 40 cos 20°|=11.65 km
The length of y-component of AC = |AB cos 80° - BC sin 20°|
=|50 cos 80° - 40 sin 20°|= 5 km
tan
= 5/11.65
=23.23°
AC=
km
Hence, the point C is 12.68 km away from the point A on a bearing of S23.23°W.
If it was 23 degrees below zero it would be -23 degrees