Answer:
Step-by-step explanation:
22) J(2,-1); K(2,5)
Distance = √(x₂-x₁)² + (y₂-y₁)²
= √( 2- 2)² + (5 - [-1] )²
= √0 + (5 + 1 )²
=√ ( 6 )² = 6
25) A(0,3) ; B (0,12)
distance =√(0-0)² + (12 - 3 )²
=√( 9)² = 9
28) Q(12,-12) ; T(5,12)
distance = √(5 - 12)² + (12 - [-12] )²
= √( -7)² + (12 + 12] )²
= √ 49 + (24)²
= √ 49 + 576
= √625
=25
9514 1404 393
Answer:
P(0, 4), Q(-3, 0)
Step-by-step explanation:
To find the y-coordinate of P, replace x with 0 and solve for y:
3y = 12
y = 4 . . . . . divide by 3
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To find the x-coordinate of Q, replace y with 0 and solve for x:
-4x = 12
x = -3 . . . . . divide by -4
Then the intercepts are P(0, 4) and Q(-3, 0). The line is drawn through those points for the indicated values of x.
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➷ It would be done in the same way it would if it was an integer ;
think of it as two separate parts
(3/5)^3 = 3/5 * 3/5 * 3/5
Calculate the top half, then the bottom half and put them together
3 * 3 * 3 = 27
5 * 5 * 5 = 125
Thus, your answer will be 27/125
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Find the domain by finding where the function is defined. The range is the set of values that correspond with the domain.
Domain: (- infinity, infinity)
Range: (- infinity, -2)
Answer:
please use a picture or something so i can help