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3 years ago

A farmer owns a total of 9 acres of land. The land is separated into 4 2/7 equally sized sections.

Mathematics

2 answers:

Soloha48 [4]3 years ago

6 0

4 2/7=30/7
9÷30/7=63/30 or 31/15 or 2 1/15. As a result, there are 2 1/15 acres in one section. Hope it help!

HACTEHA [7]3 years ago

5 0

Answer: 1 1/10

Step-by-step explanation:

A farmer owns 9 acres of land

It is divided into 4 2/7 portions equally

Therefore we have:

= 9 ÷ (4 2/7)

= 9 ÷ ( 30/7)

= 9 ×( 7/30)

Therefore we have,

= (9× 7)÷ 30

= 63/ 30

We have to find the greatest common factor (GCF), which is the largest positive integer that the numbers 63 and 30 can be divided by without leaving any remainder. That greatest common factor is 3.

We divide both numerator and denominator by 3

Therefore we have

= 21/10

Writing it in mixed number in a simple form,

= 1 1/10 .

We have 1 1/10 acres in each section.

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Find the area of a circle with a diameter of 16.

tangare [24]

Answer:

Step-by-step explanation:

Area of circle:

area = π · r · r

Radius= $\frac{16}{2}$ = 8

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2 years ago

Hi! I need help with the attached question in calc. Thank you:)

Elena L [17]

Answer:

3π square units.

Step-by-step explanation:

We can use the disk method.

Since we are revolving around AB, we have a vertical axis of revolution.

So, our representative rectangle will be horizontal.

R₁ is bounded by y = 9x.

So, x = y/9.

Our radius since our axis is AB will be 1 - x or 1 - y/9.

And we are integrating from y = 0 to y = 9.

By the disk method (for a vertical axis of revolution):

$\displaystyle V=\pi \int_a^b [R(y)]^2\, dy$

So:

$\displaystyle V=\pi\int_0^9\Big(1-\frac{y}{9}\Big)^2\, dy$

Simplify:

$\displaystyle V=\pi\int_0^9(1-\frac{2y}{9}+\frac{y^2}{81})\, dy$

Integrate:

$\displaystyle V=\pi\Big[y-\frac{1}{9}y^2+\frac{1}{243}y^3\Big|_0^9\Big]$

Evaluate (I ignored the 0):

$\displaystyle V=\pi[9-\frac{1}{9}(9)^2+\frac{1}{243}(9^3)]=3\pi$

The volume of the solid is 3π square units.

Note:

You can do this without calculus. Notice that R₁ revolved around AB is simply a right cone with radius 1 and height 9. Then by the volume for a cone formula:

$\displaystyle V=\frac{1}{3}\pi(1)^2(9)=3\pi$