Answer:
Step-by-step explanation:
y![f(x)^{-1} = inverse\\f(x)=y \\y = 1/(x^{3} \\Inverse: y=x ------------> x = 1/y^{3}\\y^{3} - \frac{1}{x} = 0\\y^{3} = \frac{1}{x}\\y = \sqrt[3]{\frac{1}{x}} \\y = \frac{\sqrt[3]{1} }{\sqrt[3]{x}} \\y = \frac{1}{\sqrt[3]{x}}](https://tex.z-dn.net/?f=f%28x%29%5E%7B-1%7D%20%20%3D%20inverse%5C%5Cf%28x%29%3Dy%20%5C%5Cy%20%3D%201%2F%28x%5E%7B3%7D%20%5C%5CInverse%3A%20y%3Dx%20------------%3E%20x%20%3D%201%2Fy%5E%7B3%7D%5C%5Cy%5E%7B3%7D%20-%20%5Cfrac%7B1%7D%7Bx%7D%20%3D%200%5C%5Cy%5E%7B3%7D%20%3D%20%5Cfrac%7B1%7D%7Bx%7D%5C%5Cy%20%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7B1%7D%7Bx%7D%7D%20%5C%5Cy%20%3D%20%5Cfrac%7B%5Csqrt%5B3%5D%7B1%7D%20%7D%7B%5Csqrt%5B3%5D%7Bx%7D%7D%20%5C%5Cy%20%3D%20%5Cfrac%7B1%7D%7B%5Csqrt%5B3%5D%7Bx%7D%7D)
∠BDC=30, so ∠CBD + ∠BCD=180-30=150
ΔDBC is isosceles, so ∠CBD=∠BCD=half of 150=75
∠ABC=∠ABD-∠CBD=155-75=80
ΔABC is isosceles, so ∠ABC=∠ACB=80
∠BAC=180-80-80=20
Answer:
156 players
Step-by-step explanation:
The 9 players for baseball and 11 players for football are added. 9 + 11 = 20.
Once you have 20, you can multiply it by the 6 schools. Which gets you 120 players so far.
After you multiply the 4 schools by the 9 players for baseball. You’ll get 36. Add the 120 players to 36 players and you’ll get 156 players for the 10 schools in total
Answer:
what did people from the Fruitlands community do in the community?
Residents of Fruitlands ate no animal substances, drank only water, bathed in unheated water and "no artificial light would prolong dark hours or cost them the brightness of morning. Additionally, property was held communally, and no animal labor was used.
Step-by-step explanation:
They would get sick from bathing in unheated water, and really scared and spooky because there was no artificial light.
All from my own words, I hope this suites your Question.
<h2>-<u>
<em>Star</em></u></h2>
Answer:
Since the calculated value of t= 2.249 does not falls in the rejection region we therefore accept the null hypothesis at 5 % significance level . On the basis of this we conclude that the bonus plan has not increased sales significantly.
Step-by-step explanation:
The null and alternative hypotheses as
H0: μd=0 Ha: μd≠0
Significance level is set at ∝= 0.05
n= 6
degrees of freedom = df = 6-1 = 5
The critical region is t ( base alpha by 2 with df=5) ≥ ± 2.571
The test statistic under H0 is
t = d/ sd/ √n
Which has t distribution with n-1 degrees of freedom
Sales Difference
Person After Before d = after - before d²
1 94 90 4 16
2 82 84 -2 4
3 90 84 6 36
4 76 70 6 36
5 79 80 -1 1
<u>6 85 80 5 25 </u>
∑ 18 118
d`= ∑d/n= 18/6= 3
sd²= 1/6( 118- 18²/6) = 1/6 ( 118 - 54) = 10.67
sd= 3.266
t= 3/ 3.266/ √6
t= 2.249
Since the calculated value of t= 2.249 does not falls in the rejection region we therefore accept the null hypothesis at 5 % significance level . On the basis of this we conclude that the bonus plan has not increased sales significantly.
