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gogolik [260]
4 years ago
7

Set y= 22x+4 and y= 14x+28 equal and solve algebraically

Mathematics
1 answer:
Doss [256]4 years ago
3 0

Answer:

x = 3; y = 70.

Step-by-step explanation:

When you set the two equations equal to each other you get:

22x + 4 = 14x + 28

This is a multi-step equation since the variable is on both sides of the equal sign.  In order to solve any equation, you must use inverse (opposite) operations to isolate the variable and whatever you do to one side of the equal sign, you must do to the other.  The first step for this equation is to get the variable on one side and the constants on the other.  Subtracting 14x from both sides:  22x - 14x + 4= 14x - 14x +28 gives us 8x +4 = 28.  Next, subtract the 4 from both sides to get:  8x +4 - 4 = 28 - 4 or 8x = 24.  Lastly, divide both sides by 8 to get x = 3.  To solve for y, simply plug 3 in for 'x' in either of the initial equations:  y = (22)(3) + 4 = 70.

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Luba_88 [7]
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twice the sum of a number and 6 is equal to 3 times the difference of the number and 8. Find the number
Serhud [2]

In order to solve this problem, we must solve an equation.

First, we need to define our unknown.

Let's call our number "n".


So, the sum of the number and 6 is the same as saying n+6

Then we need to multiply it by 2 (since it's twice the sum)

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This whole thing is equal to three times of the difference of the number and 8

n-8 is equal to the difference between the number and 8, then we need to multiply it by three.

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now, we set both sides equal and solve

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5 0
3 years ago
What is the volume of the extra large tube
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6 0
3 years ago
Sean has 1/5 of a cupcake and 1/5 of a large cake. Does the sum 1/5 + 1/5 make sense in this situation
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Answer:

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Step-by-step explanation:

3 0
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