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3 years ago

14)

2 answers:

5 0

The correct answer is C.

If she needs 45 in of white ribbon for each wreath, then she will need close to 4 feet of ribbon for each wreath. This is because 12 in = 1 foot, and 45 divided by 12 is 3.75.

If she's going to be making 18 wreaths, then she will need 3.75 feet of white ribbon for every wreath:

3.75 x 18 = 67.5.

zheka24 [161]3 years ago

4 0

Answer:

The answer is C 70 feet

Step-by-step explanation:

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You split $2000 between two savings accounts. Account a pays 2% annual interest and account b pays 5% annual interest. After one

sdas [7]

0.05x+0.02(2000-x)=77.5
0.05x+40-0.02x=77.5
(0.05-0.02)x=77.5-40
0.03x=37.5
X=37.5/0.03=1250 at 2%
2000-1250=750 at 5%

8 0

3 years ago

I NEED THIS ASAP!!!!!!!!

drek231 [11]

I know you need this bbc

6 0

3 years ago

Read 2 more answers

Does anyone know this?

barxatty [35]

Answer:

$\Huge \boxed{-2}$

Step-by-step explanation:

$f(x)=-2x^2-2x+10$

For f(2), the input of the function is 2.

Let x = 2.

$f(2)=-2(2)^2-2(2)+10$

Evaluate.

$f(2)=-2(4)-2(2)+10$

$f(2)=-8-4+10$

$f(2)=-2$

8 0

3 years ago

Read 2 more answers

Solve systems using substitution PLEASE

skad [1K]

X=5. y=35.

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4 0

2 years ago

A hyperbola centered at the origin has verticies at (add or subtract square root of 61,0 and foci at (add or subtract square roo

deff fn [24]

Answer:

$\frac{x^2}{61}-\frac{y^2}{37} =1$

Step-by-step explanation:

The standard equation of a hyperbola is given by:

$\frac{(x-h)^2}{a^2} -\frac{(y-k)^2}{b^2} =1$

where (h, k) is the center, the vertex is at (h ± a, k), the foci is at (h ± c, k) and c² = a² + b²

Since the hyperbola is centered at the origin, hence (h, k) = (0, 0)

The vertices is (h ± a, k) = (±√61, 0). Therefore a = √61

The foci is (h ± c, k) = (±√98, 0). Therefore c = √98

Hence:

c² = a² + b²

(√98)² = (√61)² + b²

98 = 61 + b²

b² = 37

b = √37

Hence the equation of the hyperbola is:

$\frac{x^2}{61}-\frac{y^2}{37} =1$

6 0

3 years ago