The situation can be modeled by a geometric sequence with an initial term of 284. The student population will be 104% of the prior year, so the common ratio is 1.04.
Let \displaystyle PP be the student population and \displaystyle nn be the number of years after 2013. Using the explicit formula for a geometric sequence we get
{P}_{n} =284\cdot {1.04}^{n}P
n
=284⋅1.04
n
We can find the number of years since 2013 by subtracting.
\displaystyle 2020 - 2013=72020−2013=7
We are looking for the population after 7 years. We can substitute 7 for \displaystyle nn to estimate the population in 2020.
\displaystyle {P}_{7}=284\cdot {1.04}^{7}\approx 374P
7
=284⋅1.04
7
≈374
The student population will be about 374 in 2020.
Answer:
Step-by-step explanation:
First FOIL (n + 7)(n + 8) and then distribute n
(n + 7)(n + 8) = 
n ()
=
Answer:
A^32
Step-by-step explanation:
Done
Answer:
a_n = 28-2n
Step-by-step explanation:
Given sequence is:
26,24,22,20
We can see that the difference between consecutive terms is same so the sequence is an arithmetic sequence
The standard formula for arithmetic sequence is:
Here,
a_n is the nth term
a_1 is the first term
and d is the common difference
So,
d = 24-26
= -2
a_1 = 26
Putting the values of d and a_1
Hence, the recursive formula for given sequence is: a_n = 28-2n ..
