Pls help I have a lot to do and it’s all due today
2 answers:
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Let;
A(-8,6) B(6,6) C(6, -4) D(-8, -4)
Let's find the length AB
x₁= -8 y₁=6 x₂=6 y₂=6
We will use the distance formula;
Next, we will find the width BC
B(6,6) C(6, -4)
x₁= 6 y₁=6 x₂=6 y₂=-4
substitute into the distance formula;
Area = l x w
= 14 x 10
= 140 square units
The given equation is a Quadratic equation, so it's graph must be a parabola, and the Coefficient of x² is positive that means the parabola must have an opening upward.
And 2 is added to the ideal equation, so the parabola must have shift 2 units up from x - axis.
From the above information, we can easily conclude that the Correct representation is done in graph 4
