12 is the answer
12 goes into all threee
If x=3
Just replace the X with 3
So seven minus three equals four
If 3 is X than do 4 times 3 which that makes twelve.
Answer and Step-by-step explanation:
Considering the table attached.
(a) over 9.5 kg;
μ = 8
σ = 0.9
z = 9.5 - 8/0.9 ≈ 1.67
P (Z > 1.67) = 0.5 - P(0<Z<1.67) = 0.5 - 0.4525 = 0.0475
(b) at most 8.6 kg;
z = 8.6-8/0.9 ≈ 0.67
P(Z < 0.67) = 0.5 + P(0<Z<0.67) = 0.5 + 0.2486 = 0.7486
(c) between 7.3 and 9.1 kg.
z₁ = 7.3-8/0.9 ≈ -0.78
z₂ = 9.1 - 8/0.9 ≈ 1.22
P(-0.78 < Z < 1.22) = P(0 < Z < 0.78) + P(0 < Z < 1.22) = 0.2823 + 0.3888 = 0.6711
To help you you should find a common denominator and then the fraction that has lower numbers is bigger
Since the dice are fair and the rolling are independent, each single outcome has probability 1/15. Every time we choose
![1\leq x\leq 3,\quad 1\leq y \leq 5](https://tex.z-dn.net/?f=1%5Cleq%20x%5Cleq%203%2C%5Cquad%201%5Cleq%20y%20%5Cleq%205)
We have
and
, because the dice are fair.
Now we use the assumption of independence to claim that
![P(X=x, Y=y) = P(X=x)\cdot P(Y=y) =\dfrac{1}{3}\cdot\dfrac{1}{5} = \dfrac{1}{15}](https://tex.z-dn.net/?f=%20P%28X%3Dx%2C%20Y%3Dy%29%20%3D%20P%28X%3Dx%29%5Ccdot%20P%28Y%3Dy%29%20%3D%5Cdfrac%7B1%7D%7B3%7D%5Ccdot%5Cdfrac%7B1%7D%7B5%7D%20%3D%20%5Cdfrac%7B1%7D%7B15%7D)
Now, we simply have to count in how many ways we can obtain every possible outcome for the sum. Consider the attached table: we can see that we can obtain:
- 2 in a unique way (1+1)
- 3 in two possible ways (1+2, 2+1)
- 4 in three possible ways
- 5 in three possible ways
- 6 in three possible ways
- 7 in two possible ways
- 8 in a unique way
This implies that the probabilities of the outcomes of
are the number of possible ways divided by 15: we can obtain 2 and 8 with probability 1/15, 3 and 7 with probability 2/15, and 4, 5 and 6 with probabilities 3/15=1/5