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3 years ago

Choose the graph below that correctly represents the equation 15x − 5y = 30.

Mathematics

2 answers:

Blababa [14]3 years ago

8 0

Answer:

it's going to be the last one

Step-by-step explanation:

Svetllana [295]3 years ago

7 0

You didn't give us a picture but I'll help you as best as I can.

First, convert the equation into the form y=mx+b:
15x-5y=30
-5y=-15x+30

Divide both sides by -5.
y=-3x-6

Below is a graph of that equation:

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A flying squirrel jumped from a tree 11 feet in the air at an initial velocity of 9 feet per sencond. The equation h=-2t^2+9t-11

vovikov84 [41]

This must be on the moon as the acceleration due to gravity in this equation must be around 1/8 that on earth. :) Anyway...

h=-2t^2+9t+11

A)

dh/dt=-4t+9, when velocity, dh/dt=0, it is the maximum height reached

dh/dt=0 only when 4t=9, t=2.25 seconds

h(2.25)=21.125 ft (21 1/8 ft)

B)

As seen in A), the time of maximum height was 2.25 seconds after the squirrel jumped.

C)

The squirrel reaches the ground when h=0...

0=-2t^2+9t+11

-2t^2-2t+11t+11=0

-2t(t+1)+11(t+1)=0

(-2t+11)(t+1)=0, since t>0 for this problem...

-2t+11=0

-2t=-11

t=5.5 seconds.

4 0

3 years ago

Read 2 more answers

Jason states that Triangle A B C is congruent to triangle R S T. Kelley states that Triangle A B C is congruent to triangle T S

Brilliant_brown [7]

Answer:

The correct option is;

Jason's statement is correct. RST is the same orientation, shape, and size as ABC

Step-by-step explanation:

Here we have

ABC = (2, 1), (3, 3), (4, 1)

RST = (-4, -2), (-3, 0), (-2, -2)

Therefore the length of the sides are as follows

AB = $\sqrt{(2-3)^2+(1-3)^2} = \sqrt{5}$

AC = $\sqrt{(2-4)^2+(1-1)^2} =2$

BC = $\sqrt{(3-4)^2+(3-1)^2} = \sqrt{5}$

For triangle SRT we have

RS = $\sqrt{(-4-(-3))^2+(-2-0)^2} = \sqrt{5}$

RT = $\sqrt{(-4-(-2))^2+(-2-(-2))^2} = 2$

ST = $\sqrt{(-3-(-2))^2+(0-(-2))^2} = \sqrt{5}$

Therefore their dimensions are equal

However the side with length 2 occurs between (2, 1) and (4, 1) in triangle ABC and between (-4, -2) and (-2, -2) in triangle RST

That is Jason's statement is correct. RST is the same orientation, shape, and size as ABC.

4 0

3 years ago

Read 2 more answers

⦁ A total of 640 people voted in an election. The circle graph shows the results. ⦁ How many people voted for Goron? Show your w

Bezzdna [24]

Circle graphs or pie charts are used to represent data in percentages or proportions

192 voted for Goron
288 voted for Smith or Fishman

<h3>People that voted for Goron</h3>

The total number of votes is given as:

Total = 640

The circle chart is not given.

So, we make use of an assumed value

Assume 30% voted for Goron

The number of people would be:

Goron = 30% * 640

Evaluate

Goron = 192

Hence, 192 voted for Goron using the assumed value

<h3>People that voted for Smith or Fishman</h3>

Assume 45% voted for Smith or Fishman

The number of people would be:

Smith or Fishman = 45% * 640

Evaluate

Smith or Fishman = 288

Hence, 288 voted for Smith or Fishman using the assumed value

Read more about circle graphs at:

brainly.com/question/24461724

8 0

2 years ago

Use the Newton-Raphson method to find the root of the equation f(x) = In(3x) + 5x2, using an initial guess of x = 0.5 and a stop

xxMikexx [17]

Answer with explanation:

The equation which we have to solve by Newton-Raphson Method is,

f(x)=log (3 x) +5 x²

$f'(x)=\frac{1}{3x}+10 x$

Initial Guess =0.5

Formula to find Iteration by Newton-Raphson method

$x_{n+1}=x_{n}-\frac{f(x_{n})}{f'(x_{n})}\\\\x_{1}=x_{0}-\frac{f(x_{0})}{f'(x_{0})}\\\\ x_{1}=0.5-\frac{\log(1.5)+1.25}{\frac{1}{1.5}+10 \times 0.5}\\\\x_{1}=0.5- \frac{0.1760+1.25}{0.67+5}\\\\x_{1}=0.5-\frac{1.426}{5.67}\\\\x_{1}=0.5-0.25149\\\\x_{1}=0.248$

$x_{2}=0.248-\frac{\log(0.744)+0.30752}{\frac{1}{0.744}+10 \times 0.248}\\\\x_{2}=0.248- \frac{-0.128+0.30752}{1.35+2.48}\\\\x_{2}=0.248-\frac{0.17952}{3.83}\\\\x_{2}=0.248-0.0468\\\\x_{2}=0.2012$

$x_{3}=0.2012-\frac{\log(0.6036)+0.2024072}{\frac{1}{0.6036}+10 \times 0.2012}\\\\x_{3}=0.2012- \frac{-0.2192+0.2025}{1.6567+2.012}\\\\x_{3}=0.2012-\frac{-0.0167}{3.6687}\\\\x_{3}=0.2012+0.0045\\\\x_{3}=0.2057$

$x_{4}=0.2057-\frac{\log(0.6171)+0.21156}{\frac{1}{0.6171}+10 \times 0.2057}\\\\x_{4}=0.2057- \frac{-0.2096+0.21156}{1.6204+2.057}\\\\x_{4}=0.2057-\frac{0.0019}{3.6774}\\\\x_{4}=0.2057-0.0005\\\\x_{4}=0.2052$