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rjkz [21]
3 years ago
14

What is the sum of the given values to the correct level of precision? 7.45 ft 10.629 ft +0.3 ft

Mathematics
2 answers:
tensa zangetsu [6.8K]3 years ago
8 0

What is the sum of the given values to the correct level of precision? 7.45 ft + 10.629 ft +0.3 ft

Answer: The sum of the given values is:

7.45 ft+10.629ft+0.3ft =18.379 ft

Therefore, the sum of the given values is 18.4 ft






kow [346]3 years ago
6 0

Answer:

c

Step-by-step explanation:

e2020

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Convert 5,283 meters to kilometers
schepotkina [342]

Step-by-step explanation:

... Kilometers

....... Hecteter

........... Dekameter

............... Meters

................... Decimeter

....................... Centimeters

........................... Millimeter

5,283 meters

= 5,283 ÷ 1,000

= 5.283 kilometers

6 0
3 years ago
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Let f(x)=151+4e−0.2x.
Jobisdone [24]

Answer:

y-intercept: (0,)

0, 4e+151

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Step-by-step explanation:

6 0
2 years ago
Find the 52nd term of the arithmetic sequence 5, 9, 13
IRINA_888 [86]

Answer:

209

Step-by-step explanation:

You would first create an explicit formula for the provided sequence.

The basic explicit formula for arithmetic sequences is a_{n} = d(n-1) + a_{1}, where an is the number of the term, d is the number you are adding or subtracting by, n the location of the term, and a1 is the first number.

We would then substitute the values given into the formula.  

We are trying to solve the value of the 52nd term. This makes n = 52. The first number of the sequence is 5, so a1 is 5. Finally, d is 4 because we are adding 4 to each number in the sequence.

Therefore, our resulting equation would be a_{n} =4(52-1)+5, which equals 209.

6 0
3 years ago
Tensile strength tests were performed on two different grades of aluminum spars used in manufacturing the wing of a commercial t
jekas [21]

Answer:

(12.1409, 14.0591

Step-by-step explanation:

Given that Tensile strength tests were performed on two different grades of aluminum spars used in manufacturing the wing of a commercial transport aircraft. From past experience with the spar manufacturing process and the testing procedure, the standard deviations of tensile strengths are assumed to be known.

Group   Group One     Group Two  

Mean 87.600 74.500

SD 1.000 1.500

SEM 0.316 0.433

N 10      12    

The mean of Group One minus Group Two equals 13.100

standard error of difference = 0.556

 90% confidence interval of this difference:  

(13.1-1.725*0.556,13.1+1.725*0.556)\\=(12.1409, 14.0591)

  t = 23.5520

 df = 20

4 0
3 years ago
Help me solve this thanks!!1 : )
S_A_V [24]

Answer:

a= -6

Step-by-step explanation:

Try Photo Math! Step by step instructions to help you understand math better!

7 0
3 years ago
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