Answer: 0.2358
Step-by-step explanation:
Using Normal Distribution, under the standard normal curve
The area to the right of z is given by P(Z>z)=1-P(Z<z)
So, the area to the right of z= 0.72 under the standard normal curve would be:
P(Z>0.72)=1-P(z<0.72)
=1-0.7642 [By using p-value table]
= 0.2358
Hence, the area to the right of z= 0.72 under the standard normal curve is 0.2358 .
Answer:
The expression is given as:
.
Step-by-step explanation:
Sophia expects the number of cows, C, on her farm t years from now to be modeled by the function:
Additionally, she expects the supply of hay, F, in tons, that her crops can provide for each cow t years from now to be modeled by the function
Let H be the total yearly amount of hay produced in Sophia's farm (in tons) t years from now.
Total amount of Hay produced in sophia's farm= Number of cows in farm×Amount of hay required for each cow.
i.e. H(t)=C(t)×F(t)
and we know that 
Hence,
.
Hence, the hay produced on Sophia's farm is used exclusively to feed her cows i.e. we need to write the formula of H ( t ) in terms of C(t) and F (t) is:
.
Answer:
P [ K > 3.95] = 0.5633
Step-by-step explanation:
The interpretation of the given question goes thus;
Suppose that K is a random variable
P[-3.95 ≤ K ≤ 3.95] = 0.725
where; P [ + 3.95 < K ] = P [K < - 3.95]
P[K< 3.95] - P [K > - 3.95] =0.725
P [K < 3.95] - [ 1- P[K < 3.95]] = 0.725
P[k < 3.95] - 1 + P [ K < 3.95] = 0.725
3.95 P [ K < 3.95] -1 = 0.725
3.95 P [ K < 3.95] = 1.725
P [ K < 3.95] = 1.725/3.95
P [ K < 3.95] = 0.4367
P [ K > 3.95] = 1 - P[K< 3.95]
P [ K > 3.95] = 1 - 0.4367
P [ K > 3.95] = 0.5633
x=3 and y=2 because 6+6 = 12 and 2 times 3 is 6 :)
Answer: x=6.8
Step-by-step explanation:
I figured it out ;)
