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taurus [48]
3 years ago
6

For the events "shower gel” and "scented” to be independent, what must be shown to be true? P(lotion) = 42% P(scented) = 42% P(s

hower gel | scented) = 42% P(scented | shower gel) = 42%
Mathematics
2 answers:
madreJ [45]3 years ago
7 0
Hi, I was able to find the full context for this one from another source:

<span>"Juanita has a storage closet at her shop with extra bottles of lotion and shower gel. Some are scented and some are unscented. If she reaches into the closet and grabs a bottle without looking, she has a 42% chance of grabbing a bottle of shower gel."

For the "shower gel" and "scented" to be independent given the situation above, we need to show that P(A | B) = P(A). You can get this equation from the definition of "independence" where P(A </span>∩ B) = P(A)*P(B) and the formula for conditional probability P(A | B).

We only have the given P(shower gel) = 42% therefore the event "shower gel" must be the variable A.

ANSWER: To show independence of the two events, P(shower gel | scented) = 42% must be true.

Aleks04 [339]3 years ago
4 0

Answer:

P (shower gel l scented) 42%

Step-by-step explanation:

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Suppose we want to build a rectangular storage container with open top whose volume is $$12 cubic meters. Assume that the cost o
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Answer:265.25

Step-by-step explanation:

Given

Volume of box=12 m^3

height is 3 times the width

let height, length and breadth be H, L & B

H=3\times B

V=12=L\times B\times H

4=B^2\times L[/tex]

L=\frac{4}{B^2}

Cost of side walls $ 8/m^2

Cost of base $ 12/m^2

Cost of side walls=(2LH+2BH)\cdot 8

Cost of base =12LB

Total cost C=16LH+16BH+12LB

C=48LB+48B^2+12LB

C=\frac{192}{B}+48B^2+\frac{48}{B}

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