-5x 2/7 =
−10x/7
srry if it is wrong man but that is what i got
Answer:
6/10 ; 3/5 (simplified form)
Step-by-step explanation:
To solve, note the decimal place value. Move the decimal point to the right two place values, and set it over 100
0.6 = 60/100
Simplify the fraction. Divide common factors from the numerator & denominator (20 in this case)
(60/100)/(20/20) = 3/5
3/5 is your answer
~
Answer: 0.1037
Step-by-step explanation:
Given : Mean : ![\mu=80\text{ miles per day}](https://tex.z-dn.net/?f=%5Cmu%3D80%5Ctext%7B%20miles%20per%20day%7D)
Standard deviation : ![\sigma = 30\text{ miles per day}](https://tex.z-dn.net/?f=%5Csigma%20%3D%2030%5Ctext%7B%20miles%20per%20day%7D)
The formula to calculate the z-score is given by :-
![z=\dfrac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D)
For x = 97 miles per day ,
![z=\dfrac{97-80}{30}\approx0.57](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7B97-80%7D%7B30%7D%5Capprox0.57)
For x = 107 miles per day ,
![z=\dfrac{97-80}{30}=0.9](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7B97-80%7D%7B30%7D%3D0.9)
The P-value =![P(0.57](https://tex.z-dn.net/?f=P%280.57%3Cz%3C0.9%29%3DP%28z%3C0.9%29-P%28z%3C0.57%29)
![=0.8159398-0.7122603=0.1036795\approx0.1037](https://tex.z-dn.net/?f=%3D0.8159398-0.7122603%3D0.1036795%5Capprox0.1037)
Hence, the probability that a truck drives between 97 and 107 miles in a day = 0.1037
Answer:
y = - 1 , x = 4
Step-by-step explanation:
The equation of a horizontal line parallel to the x- axis is
y = c
where c is the value of the y- coordinates the line passes through.
The line passes through (4, - 1 ) with y- coordinate - 1 , then
y = - 1 ← equation of horizontal line
The equation of a vertical line parallel to the y- axis is
x = c
where c is the value of the x- coordinates the line passes through.
The line passes through (4, - 1 ) with x- coordinate 4 , then
x = 4 ← equation of vertical line