Question

what is the solution to set to the inequality (4x-3)(2x-1)_>0 a) {x|x<_3 or x_>1} b) {x|x<_2 or x_> 4/3} c) {x|x&lt;_1/2 or x_>3/4} d) {x|x<_-1/2 or x_>-3/4}

Answer 1

       (4x - 3)(2x - 1) ≥ 0
4x - 3 ≥ 0    or    2x - 1 ≤ 0
    + 3  + 3                + 1 + 1
     4x ≥ 3                 2x ≤ 1
      4     4                  2    2
       x ≥ ³/₄                  x ≤ ¹/₂
        x ∈ [-∞, ¹/₂] ∧ [³/₄, ∞]

The answer is C.

Answer 2

Answer:

C

Step-by-step explanation:

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