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katovenus [111]
3 years ago
9

the half life of c14 is 5730 years. Suppose that wood found at an archeological excavation site contains about 35% as much C14 a

s does living plant material. Determine when the wood was cut
Mathematics
1 answer:
Furkat [3]3 years ago
5 0

Answer:

The wood was cut approximately 8679 years ago.

Step-by-step explanation:

At first we assume that examination occured in 2020. The decay of radioactive isotopes are represented by the following ordinary differential equation:

\frac{dm}{dt} = -\frac{m}{\tau} (Eq. 1)

Where:

\frac{dm}{dt} - First derivative of mass in time, measured in miligrams per year.

\tau - Time constant, measured in years.

m - Mass of the radioactive isotope, measured in miligrams.

Now we obtain the solution of this differential equation:

\int {\frac{dm}{m} } = -\frac{1}{\tau}\int dt

\ln m = -\frac{1}{\tau} + C

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} } (Eq. 2)

Where:

m_{o} - Initial mass of isotope, measured in miligrams.

t - Time, measured in years.

And time is cleared within the equation:

t = -\tau \cdot \ln \left[\frac{m(t)}{m_{o}} \right]

Then, time constant can be found as a function of half-life:

\tau = \frac{t_{1/2}}{\ln 2} (Eq. 3)

If we know that t_{1/2} = 5730\,yr and \frac{m(t)}{m_{o}} = 0.35, then:

\tau = \frac{5730\,yr}{\ln 2}

\tau \approx 8266.643\,yr

t = -(8266.643\,yr)\cdot \ln 0.35

t \approx 8678.505\,yr

The wood was cut approximately 8679 years ago.

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natali 33 [55]
Then that would be 3 and 9.
8 0
3 years ago
An isosceles triangle’s altitude will bisect its base. Which expression could be used to find the area of the isosceles triangle
omeli [17]

Answer:

\dfrac{\sqrt{40}\cdot \sqrt{40}}{2}

Step-by-step explanation:

The length of the base is the distance between the points 4+2i and 10+4i, so

\text{Base}=|10+4i-(4+2i)|=|10+4i-4-2i|=|6+2i|=\sqrt{6^2+2^2}=\\ \\=\sqrt{36+4}=\sqrt{40}

The middle point of the base is placed at point

\dfrac{4+2i+10+4i}{2}=\dfrac{6i+14}{2}=7+3i

The length of the height is the distance between the points 5+9i and 7+3i

\text{Height}=|5+9i-(7+3i)|=|5+9i-7-3i|=|-2+6i|=\sqrt{(-2)^2+6^2}=\\ \\=\sqrt{4+36}=\sqrt{40}

So, the area of the triangle is

A=\dfrac{1}{2}\cdot \text{Base}\cdot \text{Height}=\dfrac{\sqrt{40}\cdot \sqrt{40}}{2}

4 0
3 years ago
What is the area of circle with a diameter of 22 ft? (use 3.14 for pi; show your work in numbers)
wel

Answer:

69.08

Step-by-step explanation:

π×d

3.14×22=69.08

4 0
3 years ago
The denominator of a fraction is 4 more than the numerator if both are decreased by 3 the simplified result is 6/7 find original
Hitman42 [59]

<u>Answer:</u>

The denominator of a fraction is 4 more than the numerator. The original fraction is \frac{27}{31}

<u>Solution:</u>

Given that  

Denominator of fraction is 4 more than the numerator.

Let’s say numerator of fraction be represented by variable x.

So denominator of a faction as it is four more that numerator will be x + 4

Also given if both decreased by three than simplified result is \frac{6}{7}

=>\frac{(x-3)}{((x+4)-3)}=\frac{6}{7}

Solving above equation for x

=> 7(x – 3  ) = 6 ( x + 1 )

=> 7x – 21 = 6x + 6

=> 7x – 6x = 6 + 21

=> x = 27

Numerator of fraction = x = 27

Denominator of fraction = x + 4 = 27 + 4 = 31

\text {required fraction}=\frac{\text {numerator}}{\text {denominator}}

= \frac{27}{31}

Hence the original fraction is \frac{27}{31}

7 0
3 years ago
60 students on field trip 20 students were 8th graders. What ratio shows relationship between eighth graders and everyone who we
Flauer [41]

Answer:

Percentage=33.33%

Step-by-step explanation:

Total number of students=Number of 8th grader+others who went on trip

where;

Total number of students=60

Number of 8th graders=20

Others who went on trip=x

replacing;

60=20+x

x=(60-20)

x=40

Others who went on trip=x=40

Ratio of number of eighth graders to the number of everyone who went on the trip is;

Eighth graders who went=20 students

Everyone who went including the eighth graders=60

20/60==1/3

(1/3)×100=33.33%

Percentage=33.33%

3 0
3 years ago
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