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morpeh [17]
3 years ago
14

SHOW WORK!!!!! PLEASE HELP

Mathematics
1 answer:
aalyn [17]3 years ago
3 0

Answer:

9

Step-by-step explanation:

8 + 14 / 7 * 3 - 5

8 + 2 * 3 - 5

8 + 6 - 5

14 - 5

9

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5. Kayla is making a scale drawing of a room in a house. The room
marusya05 [52]

Answer:

he scale of a room in a blueprint is 3 in: 5 ft. A wall in the same blueprint is 18 in. ... 15. 20. 25. 30 à. How long is the actual wall? The wall is 30 feet lona. 1.5 in. b. A window in ... Redraw the rectangle on centimeter grid paper using a scale of 1 cmcom. I. leme ... measurements of the object of the drawing can you find?

Step-by-step explanation:

5 0
3 years ago
The function f(x) = x2 - 6x + 9 is shifted 5 units to the left to create g(x). What is g(x)?
creativ13 [48]

Answer:

g(x) = x^2 + 4x + 4

Step-by-step explanation:

In translation of functions, adding a constant to the domain values (x) of a function will move the graph to the left, while subtracting from the input of the function will move the graph to the right.

Given the function;

f(x) = x2 - 6x + 9

a shift 5 units to the left implies that we shall be adding the constant 5 to the x values of the function;

g(x) = f(x+5)

g(x) = (x+5)^2 - 6(x+5) + 9

g(x) = x^2 + 10x + 25 - 6x -30 + 9

g(x) = x^2 + 4x + 4

3 0
3 years ago
PLEASE RESPOND!!!
solniwko [45]

Did you ever get the answer

5 0
3 years ago
½(4k + 3r) ÷ 3^1<br><br> k = 9<br> r = 6<br><br> show work
vampirchik [111]

Answer:

The solution is given below:

Step-by-step explanation:

\\ \frac{1}{2} (4k + 3r) \div  {3}^{1}

As we know the value of k and r so the equation will be

\\ \frac{1}{2} (4 \times 9 + 3 \times 6) \div  {3}^{1}

\\  =  \frac{1}{2} (36 + 18) \div 3

\\  =  \frac{1}{2} \times 54 \div 3

\\  =  \frac{1}{2}  \times 18

\\  = 9

3 0
3 years ago
Read 2 more answers
A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and
nasty-shy [4]

Answer:

correct option is C)  2.8

Step-by-step explanation:

given data

string vibrates form =  8 loops

in water loop formed =  10 loops

solution

we consider  mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = \rho

case (1)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

so here

l = \frac{8 \lambda _1}{2}      ..............1

l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}

and we know velocity is express as

velocity = frequency × wavelength   .....................2

\sqrt{\frac{Tension}{mass\ per\ unit \length }}   =   f × \lambda_1

here tension = mg

so

\sqrt{\frac{mg}{\mu}}   =   f × \lambda_1     ..........................3

and

case (2)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

l = \frac{10 \lambda _1}{2}      ..............4

l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}

when block is immersed

equilibrium  eq will be

Tenion + force of buoyancy = mg

T + v × \rho × g = mg

and

T = v × \rho - v × \rho × g    

from equation 2

f × \lambda_2 = f  × \frac{1}{5}  

\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}     .......................5

now we divide eq 5 by the eq 3

\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}

solve irt we get

1 - \frac{\rho _{stone}}{\rho _{water}}  = \frac{16}{25}

so

relative density \frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}

relative density = 2.78 ≈ 2.8

so correct option is C)  2.8

3 0
3 years ago
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