The distance of the road junction form Timpson is given as 21.57 miles.
<h3>We have to solve this using the Pythagoras theorem method</h3>
We have AT = 
√60² + 12² = 12√26
∠TMG = LN = 90 degrees
Therefore we have the system
When we cross multiply we would have to solve for TM
TM = 21.57 miles
Hence the distance of the road junction form Timpson is given as 21.57 miles.
Read more on distance here:
brainly.com/question/17273444
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Answer:
Step-by-step explanation:
You don't multiply both of them, it's a coordinate function. There's suppose to be a comma in between
Answer:
Step-by-step explanation:
<h3>Q13</h3>
The greater the angle the greater the opposite side
<u>Sides in ascending order:</u>
- AB = 17, AC = 18, BC = 21
<u>Angles in same order</u>
<h3>Q14</h3>
<u>As above, sides in ascending order:</u>
- AB = 15, AC = 16, BC = 17
<u>Angles in same order</u>
<h3>Q15</h3>
<u>Exterior angle equals to sum of non-adjacent interior angles</u>
- 142° = x + 66°
- x = 142° - 66°
- x = 76°
<h3>Q16</h3>
<u>Same subject and isosceles triangle:</u>
- x + x = 158°
- 2x = 158°
- x = 79°
<h3>Q17</h3>
<u>Same subject</u>
- m∠QSR = m∠QPS + m∠PQS
- 2x = x + m∠PQS
- m∠PQS = 2x - x
- m∠PQS = x
ΔPQS has two angles with the measure of x, hence their opposite sides are congruent and the triangle is isosceles
Slope is 1/2. I’m here getting points lol
