10% i believe because it went up by 10 sorry if wrong
as you already know, to get the inverse of any expression we start off by doing a quick switcheroo on the variables and then solving for "y", let's do so.
![\stackrel{h(x)}{y}~~ = ~~6\sqrt[3]{2x+5}-1\implies \stackrel{\textit{quick switcheroo}}{x~~ = ~~6\sqrt[3]{2y+5}-1} \\\\\\ x+1=6\sqrt[3]{2y+5}\implies \cfrac{x+1}{6}=\sqrt[3]{2y+5}\implies \left( \cfrac{x+1}{6} \right)^3=\left( \sqrt[3]{2y+5} \right)^3](https://tex.z-dn.net/?f=%5Cstackrel%7Bh%28x%29%7D%7By%7D~~%20%3D%20~~6%5Csqrt%5B3%5D%7B2x%2B5%7D-1%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bquick%20switcheroo%7D%7D%7Bx~~%20%3D%20~~6%5Csqrt%5B3%5D%7B2y%2B5%7D-1%7D%20%5C%5C%5C%5C%5C%5C%20x%2B1%3D6%5Csqrt%5B3%5D%7B2y%2B5%7D%5Cimplies%20%5Ccfrac%7Bx%2B1%7D%7B6%7D%3D%5Csqrt%5B3%5D%7B2y%2B5%7D%5Cimplies%20%5Cleft%28%20%5Ccfrac%7Bx%2B1%7D%7B6%7D%20%5Cright%29%5E3%3D%5Cleft%28%20%5Csqrt%5B3%5D%7B2y%2B5%7D%20%5Cright%29%5E3)

>
absolute 17 would be greater because the absolute signs cancel out the negatives
Answer: 8 1/4g/cm³
Step-by-step explanation:
Given the graph :
The rate of change in the mass of copper with respect to volume :
To obtain this, we find the slope or gradient of the graph:
Gradient = Δy / Δx = (y2 - y1) / (x2 - x1)
Drawing a right angled triangle on the anybpart of the line of best fit:
y2 = 40 ; x2 = 4.75 ; y1 = 16 ; x1 = 2
(y2 - y1) / (x2 - x1)
= (40 -16) / (4.75 - 2)
= 24 / 2.75
= 2400/275
= 8.727 g/cm^3
Due to unit and graph scale,, the slope is closest to 8 1/4g/cm³