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Morgarella [4.7K]

4 years ago

8

lara chooses a square number she rounds it to the nearest hundred her answer is200 write all the possible square numbers lara co

uld have chosen

1 answer:

velikii [3]4 years ago

7 0

169 (13 squared) 196 (14) 225 (15)

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Expand<br> c(3c - 3)<br> I need help on this

Rudik [331]

$\\ \sf\longmapsto c(3c-3)$

Apply distributive law

a(b-d)=ab-ad

$\\ \sf\longmapsto 3c(c)-3(c)$

$\\ \sf\longmapsto 3c^2-3c$

We can still take common

$\\ \sf\longmapsto 3c(c-1)$

4 0

3 years ago

Read 2 more answers

9. Factorize: 6x2 - 19x + 14.

Stella [2.4K]

Answer:

Step-by-step explanation:

Here, we want to factor the given polynomial

We have this as;

6x^2 - 19x + 14

= 6x^2 -12x-7x + 14

= 6x(x-2) -7(x-2)

= (6x-7)(x-2)

6x^2-19x + 14 = (6x-7)(x-2)

4 0

3 years ago

working together Jacob and Kayla can clan an attic in 4.24 hours. had she done it alone it would have taken Kayla nine hours. ho

Marizza181 [45]

That’s not enough information to say how long he could do it. He could go slower or faster than her but by how much if so. So it’s not enough info.

5 0

4 years ago

BRAINLIEST FOR THE FIGHT ANSWER!!!

Gemiola [76]

= .91(.85)(.82) = .63427
<span>or 63.427% of the original price

so your answer is B</span>

3 0

4 years ago

I need the answer for this exact question

denis23 [38]

Answer:

$y=\frac{7}{2}x-20$

Step-by-step explanation:

Let the equation of the line be $y-y_1=m(x-x_1)$ where, 'm' is its slope and $(x_1,y_1)$ is a point on it.

Given:

The equation of a known line is:

$y=-\frac{2}{7}x+9$

A point on the unknown line is:

$(x_1,y_1)=(4,-6)$

Both the lines are perpendicular to each other.

Now, the slope of the known line is given by the coefficient of 'x'. Therefore, the slope of the known line is $m_1=-\frac{2}{7}$

When two lines are perpendicular, the product of their slopes is equal to -1.

Therefore,

$m\cdot m_1=-1\\m=-\frac{1}{m_1}\\m=-\frac{1}{\frac{-2}{7} }=\frac{7}{2}$

Therefore, the equation of the unknown line is determined by plugging in all the given values. This gives,

$y-(-6))=\frac{7}{2}(x-4)\\y+6=\frac{7}{2}x-14\\y=\frac{7}{2}x-14-6\\\\y=\frac{7}{2}x-20$

The equation of a line perpendicular to the given line and passing through (4, -6) is $y=\frac{7}{2}x-20$ .

3 0

3 years ago